android.os.NetworkOnMainThreadException。需要使用异步任务？ [英] android.os.NetworkOnMainThreadException . Need to use async task?
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问题描述
我有我的android登录功能有问题，越来越 android.os.NetworkOnMainThreadException
我去掉了密码字段只是现在来测试，如果只是用户名已被张贴，我知道，这是为Android 3.2 +的一个问题。
下面是我的code：
包com.example.toknapp;
进口的java.util.ArrayList;
公共类Login2身份延伸活动{
联合国的EditText;
TextView的错误;
OK按钮;
/ **第一次创建活动时调用。 * /
@覆盖
公共无效的onCreate（包savedInstanceState）{
super.onCreate（savedInstanceState）;
的setContentView（R.layout.login）;
UN =（EditText上）findViewById（R.id.et_un）;
OK =（按钮）findViewById（R.id.btn_login）;
误差=（TextView中）findViewById（R.id.tv_error）;
ok.setOnClickListener（新View.OnClickListener（）{
@覆盖
公共无效的onClick（视图v）{
// TODO自动生成方法存根
ArrayList的＆LT;的NameValuePair＆GT; postParameters =新的ArrayList＆LT;的NameValuePair＆GT;（）;
postParameters.add（新BasicNameValuePair（用户名，un.getText（）的toString（）））;
//字符串有效=1;
串响应=无效;
尝试 {
响应= CustomHttpClient.executeHttpPost（http://tokn.me/android_merchant_login.php，postParameters）;
字符串解析度= response.toString（）;
//解析度= res.trim（）;
RES = res.replaceAll（\\ S +，）;
//error.setText(res）;
如果（res.equals（1））
error.setText（正确的用户名和密码）;
其他
error.setText（对不起！不正确的用户名或密码）;
}赶上（例外五）{
un.setText（e.toString（））;
}
}
}）;
}
}
包com.example.toknapp;
进口java.io.BufferedReader中;
进口java.io.IOException异常;
进口java.io.InputStreamReader中;
进口java.net.URI中;
进口的java.util.ArrayList;
进口org.apache.http.Htt presponse;
进口org.apache.http.NameValuePair;
进口org.apache.http.client.HttpClient;
进口org.apache.http.client.entity.UrlEn codedFormEntity;
进口org.apache.http.client.methods.HttpGet;
进口org.apache.http.client.methods.HttpPost;
进口org.apache.http.conn.params.ConnManagerParams;
进口org.apache.http.impl.client.DefaultHttpClient;
进口org.apache.http.params.HttpConnectionParams;
进口org.apache.http.params.HttpParams;
公共类CustomHttpClient {
/ **所花费的时间为我们的客户超时* /
公共静态最终诠释HTTP_TIMEOUT = 30 * 1000; //毫秒
/ **我们的HttpClient单实例* /
私有静态HttpClient的mHttpClient;
/ **
*获取我们的单我们HttpClient的对象实例。
*
返回：一个HttpClient的对象连接参数设置
* /
私有静态HttpClient的getHttpClient（）{
如果（mHttpClient == NULL）{
mHttpClient =新DefaultHttpClient（）;
最后的HttpParams PARAMS = mHttpClient.getParams（）;
HttpConnectionParams.setConnectionTimeout（参数，可以HTTP_TIMEOUT）;
HttpConnectionParams.setSoTimeout（参数，可以HTTP_TIMEOUT）;
ConnManagerParams.setTimeout（参数，可以HTTP_TIMEOUT）;
}
返回mHttpClient;
}
/ **
*执行一个HTTP POST请求到指定的URL与
*指定的参数。
*
*参数的URL网址张贴请求
*参数postParameters的参数通过发送请求
返回：所述请求的结果
* @throws异常
* /
公共静态字符串executeHttpPost（字符串URL，ArrayList的＆LT;的NameValuePair＆GT; postParameters）抛出异常{
BufferedReader中的= NULL;
尝试 {
HttpClient的客户= getHttpClient（）;
HttpPost请求=新HttpPost（URL）;
UrlEn codedFormEntity formEntity =新UrlEn codedFormEntity（postParameters）;
request.setEntity（formEntity）;
HTT presponse响应= client.execute（要求）;
在=新的BufferedReader（新的InputStreamReader（response.getEntity（）的getContent（）））;
StringBuffer的SB =新的StringBuffer（）;
串线=;
串NL = System.getProperty（line.separator）;
而（（行= in.readLine（））！= NULL）{
sb.append（行+ NL）;
}
附寄（）;
字符串结果= sb.toString（）;
返回结果;
} 最后 {
如果（在！= NULL）{
尝试 {
附寄（）;
}赶上（IOException异常E）{
e.printStackTrace（）;
}
}
}
}
/ **
*执行一个HTTP GET请求到指定的URL。
*
*参数的URL网址张贴请求
返回：所述请求的结果
* @throws异常
* /
公共静态字符串executeHttpGet（字符串URL）抛出异常{
BufferedReader中的= NULL;
尝试 {
HttpClient的客户= getHttpClient（）;
HTTPGET请求=新HTTPGET（）;
request.setURI（新的URI（URL））;
HTT presponse响应= client.execute（要求）;
在=新的BufferedReader（新的InputStreamReader（response.getEntity（）的getContent（）））;
StringBuffer的SB =新的StringBuffer（）;
串线=;
串NL = System.getProperty（line.separator）;
而（（行= in.readLine（））！= NULL）{
sb.append（行+ NL）;
}
附寄（）;
字符串结果= sb.toString（）;
返回结果;
} 最后 {
如果（在！= NULL）{
尝试 {
附寄（）;
}赶上（IOException异常E）{
e.printStackTrace（）;
}
}
}
}
}
解决方案
我想你想peform在你的主线程的一些网络操作
NetworkOnMainThreadException 从文档
的异常当应用程序试图执行时引发 联网运行其主线程。
更新：
它能够更好地使用的AsyncTask
私有类MyAsyncTask扩展的AsyncTask＆LT;虚空，虚空，虚空＆GT;
{
ProgressDialog mProgressDialog;
@覆盖
保护无效onPostExecute（无效的结果）{
mProgressDialog.dismiss（）;
}
@覆盖
在preExecute保护无效（）{
mProgressDialog = ProgressDialog.show（ActivityName.this，
载入中...，数据载入中......）;
}
@覆盖
保护无效doInBackground（虚空...... PARAMS）{
//你的网络操作
返回null;
}
}
I'm having a problem with my android login functionality, getting android.os.NetworkOnMainThreadException
I removed the password field just for now to test if just the username was being posted, I'm aware that this is a problem for android 3.2+.
Here is my code:
package com.example.toknapp;
import java.util.ArrayList;
public class login2 extends Activity {
EditText un;
TextView error;
Button ok;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.login);
un=(EditText)findViewById(R.id.et_un);
ok=(Button)findViewById(R.id.btn_login);
error=(TextView)findViewById(R.id.tv_error);
ok.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("username", un.getText().toString()));
//String valid = "1";
String response = null;
try {
response = CustomHttpClient.executeHttpPost("http://tokn.me/android_merchant_login.php", postParameters);
String res=response.toString();
// res = res.trim();
res= res.replaceAll("\\s+","");
//error.setText(res);
if(res.equals("1"))
error.setText("Correct Username or Password");
else
error.setText("Sorry!! Incorrect Username or Password");
} catch (Exception e) {
un.setText(e.toString());
}
}
});
}
}
package com.example.toknapp;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URI;
import java.util.ArrayList;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.conn.params.ConnManagerParams;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.params.HttpConnectionParams;
import org.apache.http.params.HttpParams;
public class CustomHttpClient {
/** The time it takes for our client to timeout */
public static final int HTTP_TIMEOUT = 30 * 1000; // milliseconds
/** Single instance of our HttpClient */
private static HttpClient mHttpClient;
/**
* Get our single instance of our HttpClient object.
*
* @return an HttpClient object with connection parameters set
*/
private static HttpClient getHttpClient() {
if (mHttpClient == null) {
mHttpClient = new DefaultHttpClient();
final HttpParams params = mHttpClient.getParams();
HttpConnectionParams.setConnectionTimeout(params, HTTP_TIMEOUT);
HttpConnectionParams.setSoTimeout(params, HTTP_TIMEOUT);
ConnManagerParams.setTimeout(params, HTTP_TIMEOUT);
}
return mHttpClient;
}
/**
* Performs an HTTP Post request to the specified url with the
* specified parameters.
*
* @param url The web address to post the request to
* @param postParameters The parameters to send via the request
* @return The result of the request
* @throws Exception
*/
public static String executeHttpPost(String url, ArrayList<NameValuePair> postParameters) throws Exception {
BufferedReader in = null;
try {
HttpClient client = getHttpClient();
HttpPost request = new HttpPost(url);
UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters);
request.setEntity(formEntity);
HttpResponse response = client.execute(request);
in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer sb = new StringBuffer("");
String line = "";
String NL = System.getProperty("line.separator");
while ((line = in.readLine()) != null) {
sb.append(line + NL);
}
in.close();
String result = sb.toString();
return result;
} finally {
if (in != null) {
try {
in.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
/**
* Performs an HTTP GET request to the specified url.
*
* @param url The web address to post the request to
* @return The result of the request
* @throws Exception
*/
public static String executeHttpGet(String url) throws Exception {
BufferedReader in = null;
try {
HttpClient client = getHttpClient();
HttpGet request = new HttpGet();
request.setURI(new URI(url));
HttpResponse response = client.execute(request);
in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer sb = new StringBuffer("");
String line = "";
String NL = System.getProperty("line.separator");
while ((line = in.readLine()) != null) {
sb.append(line + NL);
}
in.close();
String result = sb.toString();
return result;
} finally {
if (in != null) {
try {
in.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
}
解决方案
I guess you are trying to peform some Network operation on your main thread
NetworkOnMainThreadException from the Docs
The exception that is thrown when an application attempts to perform a networking operation on its main thread.
UPDATE:
Its Better to use AsyncTask
private class MyAsyncTask extends AsyncTask<Void, Void, Void>
{
ProgressDialog mProgressDialog;
@Override
protected void onPostExecute(Void result) {
mProgressDialog.dismiss();
}
@Override
protected void onPreExecute() {
mProgressDialog = ProgressDialog.show(ActivityName.this,
"Loading...", "Data is Loading...");
}
@Override
protected Void doInBackground(Void... params) {
// your network operation
return null;
}
}
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