找到python代码发生异常的行号 [英] Locating the line number where an exception occurs in python code

问题描述

我有一个与此相似的代码：

I have a code similar to this:

try:
  if x:
      statement1
      statement2
      statement3
  elif y:
      statement4
      statement5
      statement6
  else:
      raise

except:
      statement7

在这里，我确信这个例外发生在如果x：阻止，但我想知道在哪个语句如果x：阻止异常发生。有没有办法得到异常发生的行号？

Here, I am sure that the exception occurs in If x: block, but I would like to know in which statement of If x: block the exception occurs. Is there a way to get the line number where the exception occurs?

请问，

推荐答案

这是什么：

try:
  if x:
      print 'before statement 1'
      statement1
      print 'before statement 2' #ecc. ecc.
      statement2
      statement3
  elif y:
      statement4
      statement5
      statement6
  else:
      raise

except:
      statement7

这是一个简单的解决方法，但我建议使用调试器

this is the straightforward workaround but I suggest to use a debugger

甚至更好，使用sys模块：D

or even better, use the sys module :D

try:
      if x:
          print 'before statement 1'
          statement1
          print 'before statement 2' #ecc. ecc.
          statement2
          statement3
      elif y:
          statement4
          statement5
          statement6
      else:
          raise
except:
    print sys.exc_traceback.tb_lineno 
    #this is the line number, but there are also other infos

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