org.json.JSONException：类型为java.lang.String的值不能转换为JSONObject [英] org.json.JSONException: Value of type java.lang.String cannot be converted to JSONObject

问题描述

我看到其他主题，他们正在谈论的是编码（服务器）或其他的东西服务器端，但我试图把所有我的JSON字段中的测试一个问题仍然存在。

这是我的代码：

  URL url = new URL（c.getString（R.string.url_ws）+ url_ws）; 
 HttpURLConnection connection =（HttpURLConnection）url.openConnection（）; 
 connection.setDoOutput（true）; 
 connection.setRequestProperty（Content-Type，application / x-www-form-urlencoded）; 
 connection.setRequestMethod（POST）; 
 OutputStreamWriter request = new OutputStreamWriter（connection.getOutputStream（））; 
 request.write（& test = test）; 
 request.flush（）; 
 request.close（）; 
 
 
字符串; 
 InputStreamReader isr = new InputStreamReader（connection.getInputStream（））; 
 BufferedReader reader = new BufferedReader（isr）; 
 StringBuilder sb = new StringBuilder（）; 
 
 while（（line = reader.readLine（））！= null）{
 sb.append（line +\\\
）; 
} 
 String json = sb.toString（）。trim（）; 
 try {
 JSONObject obj = new JSONObject（json）; 
} catch（JSONException e）{
 e.printStackTrace（）; 
 Log.d（Tools.TAG +/ debug JSONException，e.toString（））; 
返回null; 
} 
  

这是我的例外

调用JSONException（4184）：org.json.JSONException：类型为java.lang.String的值不能转换为JSONObject

我看到Value和of之间的空格，所以我猜问题是一个空字符串，但我没有得到它。

谢谢。

编辑

我的JSON中的编码错误，

  char a = json.substring（0，1）.charAt（0）; 
 int ascii =（int）a; 
 Tools.myLog（>+ ascii +<）; 
  

我发现65279 char

解决方案

为什么& ＃65279;出现在我的HTML？

编码没有BOM的UTF-8。

解决方案

  while（（line = reader.readLine（））！= null）{
 sb.append（line +\\\
）; 
} 
  

而不是尝试

  while（（line = reader.readLine（））！= null）{
 sb.append（line）; 
 json = sb.toString（）。substring（0，sb.toString（）。length（） -  1）; 
} 
  

按照此方法获取json对象：

  public JSONObject getJSONObjFromUrl（String url，List< NameValuePair> params）{
 System.out.println（url ::+ url）; 
 System.out.println（params ::+ params ++ params.get（0））; 
 //进行HTTP请求
 try {
 // defaultHttpClient 
 DefaultHttpClient httpClient = new DefaultHttpClient（）; 
 HttpPost httpPost = new HttpPost（url）; 
 httpPost.setEntity（new UrlEncodedFormEntity（params））; 
 
 HttpResponse httpResponse = httpClient.execute（httpPost）; 
 HttpEntity httpEntity = httpResponse.getEntity（）; 
 is = httpEntity.getContent（）; 
 
} catch（UnsupportedEncodingException e）{
 e.printStackTrace（）; 
} catch（ClientProtocolException e）{
 e.printStackTrace（）; 
} catch（IOException e）{
 e.printStackTrace（）; 
} 
 
 try {
 BufferedReader reader = new BufferedReader（new InputStreamReader（
 is，iso-8859-1），8）; 
 StringBuilder sb = new StringBuilder（）; 
 String line = null; 
 while（（line = reader.readLine（））！= null）{
 sb.append（line）; 
} 
 is.close（）; 
 
 json = sb.toString（）。substring（0，sb.toString（）。length（） -  1）; 
 // Log.e（JSON ::，json）; 
} catch（Exception e）{
 Log.e（缓冲区错误，转换结果错误+ e.toString（））; 
} 
 
 //尝试将字符串解析为JSON对象
 try {
 jObj = new JSONObject（json）; 
} catch（JSONException e）{
 Log.e（JSON Parser，解析数据错误+ e.toString（））; 
} 
 
 //返回JSON String 
 
 return jObj; 
 
} 
  

Hi i got a problem with Android JSON Parser in 2.3, all is ok in 4.0>.

I look other topic they are talking about encoding (server) or other stuff server side, but i tried to put "test" in all my JSON field an the problem still persist.

Here is my code :

URL url = new URL(c.getString(R.string.url_ws) + url_ws);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setRequestMethod("POST");
OutputStreamWriter request = new OutputStreamWriter(connection.getOutputStream());
request.write("&test=test");
request.flush();
request.close();


String line;
InputStreamReader isr = new InputStreamReader(connection.getInputStream());
BufferedReader reader = new BufferedReader(isr);
StringBuilder sb = new StringBuilder();

while ((line = reader.readLine()) != null){
    sb.append(line + "\n");
}
String json = sb.toString().trim();
try {
     JSONObject obj = new JSONObject(json);
} catch (JSONException e) {
    e.printStackTrace();
    Log.d(Tools.TAG+"/debug JSONException", e.toString());
    return null;
}

Here is my exception

debug JSONException(4184): org.json.JSONException: Value  of type java.lang.String cannot be converted to JSONObject

i saw double space between "Value" and "of" so i guess the problem is a empty string but i dont get it.

thanks.

EDIT

it was a encode mistake in my JSON,

char a = json.substring(0, 1).charAt(0);
int ascii = (int)a;
Tools.myLog(">"+ascii+"<"); 

i found 65279 char

SOLUTION

Why is  appearing in my HTML?

encoding UTF-8 without BOM.

解决方案

while ((line = reader.readLine()) != null){
    sb.append(line + "\n");
}

instead try

while ((line = reader.readLine()) != null){
    sb.append(line);
   json = sb.toString().substring(0, sb.toString().length()-1);
}

Follow this method for getting json object:

 public JSONObject getJSONObjFromUrl(String url, List<NameValuePair> params) {      
            System.out.println("url:: "+url );
            System.out.println("params:: "+ params +" " +params.get(0) );
            // Making HTTP request
            try {
                // defaultHttpClient
                DefaultHttpClient httpClient = new DefaultHttpClient();
                HttpPost httpPost = new HttpPost(url);
                httpPost.setEntity(new UrlEncodedFormEntity(params));

                HttpResponse httpResponse = httpClient.execute(httpPost);
                HttpEntity httpEntity = httpResponse.getEntity();
                is = httpEntity.getContent();

            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }

            try {
                BufferedReader reader = new BufferedReader(new InputStreamReader(
                        is, "iso-8859-1"), 8);
                StringBuilder sb = new StringBuilder();
                String line = null;
                while ((line = reader.readLine()) != null) {
                    sb.append(line);
                }
                is.close();

                json = sb.toString().substring(0, sb.toString().length()-1);
               // Log.e("JSON:: ", json);
            } catch (Exception e) {
                Log.e("Buffer Error", "Error converting result " + e.toString());
            }

            // try parse the string to a JSON object
            try {
                jObj = new JSONObject(json);
            } catch (JSONException e) {
                Log.e("JSON Parser", "Error parsing data " + e.toString());
            }

            // return JSON String

            return jObj;

        }

这篇关于org.json.JSONException：类型为java.lang.String的值不能转换为JSONObject的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！