Android studio，错误：org.json.jsonexception：类型为java.lang.string的customerid的值无法转换为int [英] Android studio, error: org.json.jsonexception: value at customerid of type java.lang.string cannot be converted to int

问题描述

好友，



成功登录后，我正在尝试使用REST网络服务下载数据。解析时我收到错误：org.json.JSONException：类型为java.lang.String的CustomerId的值无法转换为int

------------- ----------

public static void Download_Data（int UserId，String wsUsername，String wsPassword，boolean isDbProd，

Object callBackClass，Method callBackMethod）throws例外

{

downloadDataCallBackClass = callBackClass;

downloadDataCallBackMethod = callBackMethod;



尝试{

方法dlGetData = DL.class.getMethod（downloadDataResult，JSONObject.class，Exception.class）;



Map<串，> parameters = new HashMap< string，>（）;

parameters.put（UserId，UserId）;

parameters.put（wsUsername，wsUsername）;

parameters.put（wsPassword，wsPassword）;

parameters.put（IsDbProduction，isDbProd）;



new WebService_Call（）。execute（URL，NAMESPACE，http://tempuri.org/+ WebMethods.android_GetData.toString（），

WebMethods.android_GetData.toString（）， DL.class，dlGetData，参数）;

}

catch（例外e）

{

全新例外（DL.Get_Data（）：\ n+ e.getMessage（））;

}

}

--- -----------------------------

public static void downloadDataResult（JSONObject JSO，Exception e）抛出异常{

尝试{

if（e == null）{

DL.downloadDataInfo = JS O.getJSONArray（Items）。getJSONObject（0）;

saveItems（）;

}

downloadDataCallBackMethod.invoke（downloadDataCallBackClass，JSO ，e）;

} catch（Exception ex）{

ex.printStackTrace（）;

}

}

--------------------------------

public static void saveItems（）

{

DBHelper helper = new DBHelper（context）;

ItemDL items = new ItemDL（）;



//解析JSON数据......

尝试{

items.setItemId（DL.downloadDataInfo.getInt（ ItemId））;

items.setItemCode（DL.downloadDataInfo.getString（ItemCode））;

items.setCustName（DL.downloadDataInfo.getString（CustomerName） ））;

items.setCustMobile（DL.downloadDataInfo.getString（CustomerMobile））;

items.setErrMsg （DL.downloadDataInfo.getString（ErrorMsg））;

items.setProcedureId（DL.downloadDataInfo.getInt（ProcedureId））;

items.setStatementId（DL .downloadDataInfo.getInt（StatmentID））;

items.setCustomerId（DL.downloadDataInfo.getInt（CustomerId））; < - 这行代码抛出异常

items.setExceptionId（DL.downloadDataInfo.getInt（ExceptionID））;

items.setInserted（DL.downloadDataInfo。 getBoolean（IsInserted））;



helper.insertItems（items）;

} catch（异常e）{

e.printStackTrace（）;

System.out.println（Thrown Exception：+ e.getMessage（））;

}

}

------------------------------------- -

我从这行代码中得到错误：items.setCustomerId（DL.downloadDataInfo.getInt（CustomerId））;

------ --------------------------------

返回的JSON对象：



{ItemCode：EE4xyzxyx，

ItemId：55452134，

ExceptionID： - 1 ，

ErrorMsgNo：，

Lat：，

UserID：6510，

UserName：，

IsInserted：，

客户名称：，

CustomerMobile：，

PostServiceId： - 1，

Sp_Status：，

CustomerId：，

ProcedureId：198，

UserFullName： aasafe，

ImagePic：，

StatmentID： - 1，

ErrorMsg： ，

Lon：}

-------------------------- ---

亲切检查，让我知道我做错了什么。



我尝试过：



Android Studio，错误：org.json.JSONException：类型为java.lang.String的CustomerId上的值无法转换为int

Friends,

After successful login, I'm trying to download data using REST web service. While parsing I'm getting error : org.json.JSONException: value at CustomerId of type java.lang.String cannot be converted to int
-----------------------
public static void Download_Data(int UserId, String wsUsername, String wsPassword, boolean isDbProd,
Object callBackClass, Method callBackMethod) throws Exception
{
downloadDataCallBackClass=callBackClass;
downloadDataCallBackMethod=callBackMethod;

try {
Method dlGetData=DL.class.getMethod("downloadDataResult",JSONObject.class,Exception.class);

Map<string,> parameters=new HashMap<string,>();
parameters.put("UserId",UserId);
parameters.put("wsUsername",wsUsername);
parameters.put("wsPassword",wsPassword);
parameters.put("IsDbProduction",isDbProd);

new WebService_Call().execute(URL, NAMESPACE, "http://tempuri.org/" + WebMethods.android_GetData.toString(),
WebMethods.android_GetData.toString(), DL.class, dlGetData, parameters);
}
catch (Exception e)
{
throw new Exception("DL.Get_Data():\n" + e.getMessage());
}
}
--------------------------------
public static void downloadDataResult(JSONObject JSO,Exception e)throws Exception {
try {
if (e == null) {
DL.downloadDataInfo = JSO.getJSONArray("Items").getJSONObject(0);
saveItems();
}
downloadDataCallBackMethod.invoke(downloadDataCallBackClass, JSO, e);
} catch (Exception ex) {
ex.printStackTrace();
}
}
--------------------------------
public static void saveItems()
{
DBHelper helper = new DBHelper(context);
ItemDL items=new ItemDL();

//parse JSON DATA...
try {
items.setItemId(DL.downloadDataInfo.getInt("ItemId"));
items.setItemCode(DL.downloadDataInfo.getString("ItemCode"));
items.setCustName(DL.downloadDataInfo.getString("CustomerName"));
items.setCustMobile(DL.downloadDataInfo.getString("CustomerMobile"));
items.setErrMsg(DL.downloadDataInfo.getString("ErrorMsg"));
items.setProcedureId(DL.downloadDataInfo.getInt("ProcedureId"));
items.setStatementId(DL.downloadDataInfo.getInt("StatmentID"));
items.setCustomerId(DL.downloadDataInfo.getInt("CustomerId")); <-- This line of code throws exception
items.setExceptionId(DL.downloadDataInfo.getInt("ExceptionID"));
items.setInserted(DL.downloadDataInfo.getBoolean("IsInserted"));

helper.insertItems(items);
} catch (Exception e) {
e.printStackTrace();
System.out.println("Thrown Exception: "+e.getMessage());
}
}
--------------------------------------
I'm getting Error from this line of code: items.setCustomerId(DL.downloadDataInfo.getInt("CustomerId"));
--------------------------------------
Returned JSON Object:

{"ItemCode":"EE4xyzxyx",
"ItemId":"55452134",
"ExceptionID":"-1",
"ErrorMsgNo":"",
"Lat":"",
"UserID":"6510",
"UserName":"",
"IsInserted":"",
"CustomerName":"",
"CustomerMobile":"",
"PostServiceId":"-1",
"Sp_Status":"",
"CustomerId":"",
"ProcedureId":"198",
"UserFullName":"aasafe",
"ImagePic":"",
"StatmentID":"-1",
"ErrorMsg":"",
"Lon":""}
-----------------------------
Kind check and let me know what I'm doing wrong.

What I have tried:

Android Studio, Error: org.json.JSONException: value at CustomerId of type java.lang.String cannot be converted to int

推荐答案

您正在调用 getInt 来检索非整数的值。使用 getString ，如错误消息所示。

You are calling getInt to retreive a value that is not an integer. Use getString as indicated by the error message.

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