java.lang.String类型的com.android.volley.parse错误org.json.jsonexception价值不能在Android的凌空转换为jsonArray [解决] [英] com.android.volley.parse error org.json.jsonexception value of type java.lang.string cannot be converted to jsonArray in Android Volley [SOLVED]

问题描述

当我运行这个程序，我得到这个错误。我不知道如何解决。帮我找到它请。

这是我的json_en code PHP code API。

  $ I = 0;
  而（$行= $ result-＆GT; FETCH_ASSOC（））
  {
   $阵列[$ i] =阵列（
        news_id=＆GT; $行[news_id]，
        news_title=＆GT; $行[news_title]，
        news_abstract=＆GT; $行[news_abstract]，
        news_content=＆GT; $行[news_content]，
        news_date=＆GT; $行[news_date]，
        NEWS_LINK=＆GT; $行[NEWS_LINK]，
        news_image_link=＆GT; $行[news_image_link]，
        sources_name=＆GT; $行[sources_name]，
        CATEGORY_NAME=＆GT; $行[CATEGORY_NAME]，
        news_visible=＆GT; $行[news_visible]
    ）;
    $ I ++;
  }
    $ JSON = json_en code（$数组）;
 

和我的Andr​​oid排球JsonArrayRequest的JsonArrayRequest。

  JsonArrayRequest newsRequest =新JsonArrayRequest（Url.getUrlJson（），新Response.Listener＆LT; JSONArray＆GT;（）{
        @覆盖
        公共无效onResponse（JSONArray响应）{
            Log.d（TAG，response.toString（））;
            hidePDialog（）;            //解析JSON
            的for（int i = 0; I＆LT; response.length（）;我++）{
                尝试{
                    JSONObject的OBJ = response.getJSONObject（I）
                    新闻新闻=新新闻（）;
                     如果（1.equals（obj.getString（news_visible）））{                        news.setNews_id（obj.getString（news_id））;
                        news.setNews_title（obj.getString（news_title））;
                        news.setNews_abstract（obj.getString（news_abstract））;
                        news.setNews_content（obj.getString（news_content））;
                        news.setNews_date（obj.getString（news_date））;
                        news.setNews_link（obj.getString（NEWS_LINK））;
                        news.setNews_image_link（obj.getString（news_image_link））;
                        news.setSources_name（obj.getString（sources_name））;
                        news.setCategory_name（obj.getString（CATEGORY_NAME））;
                    }
                    newsList.add（新闻）;
                }
                赶上（JSONException E）{
                    e.printStackTrace（）;
                }
 

解决方案

内容类型

 ＆LT; PHP
标题（内容类型：应用程序/ JSON'）;
 

请参阅从PHP脚本返回的JSON

字节顺序标记

PHP是容易返回的 BOM 的在反应，开始的时候在的.php 文件或任何其<$ C $的C>包含活动的UTF-8字符编码。

有关更多信息，请参见这个W3C答案以及部分 UTF-8 BOM在这个岗位

一位代表建议的方法prevent PHP从prepending一个BOM是<一个href=\"http://stackoverflow.com/questions/64860/best-way-to-convert-text-files-between-character-sets\">change字符从UTF-8设置你的PHP文件（S）以ASCII或ISO-8859-15。

When I run this program I get this error . I don't know how to solve . Help me finding it Please.

This is my json_encode php code api.

  $i=0;
  while ($row = $result->fetch_assoc())
  {
   $array[$i]=array(
        "news_id" => $row["news_id"], 
        "news_title" => $row["news_title"], 
        "news_abstract" => $row["news_abstract"], 
        "news_content" => $row["news_content"], 
        "news_date" => $row["news_date"], 
        "news_link" => $row["news_link"], 
        "news_image_link" => $row["news_image_link"], 
        "sources_name" => $row["sources_name"], 
        "category_name" => $row["category_name"],
        "news_visible" => $row["news_visible"]
    );
    $i++;
  }
    $json=json_encode($array);

and my JsonArrayRequest of Android Volley JsonArrayRequest.

JsonArrayRequest newsRequest = new JsonArrayRequest( Url.getUrlJson(), new  Response.Listener<JSONArray>(){
        @Override
        public void onResponse( JSONArray response ){
            Log.d( TAG, response.toString() );
            hidePDialog();

            // Parsing json
            for( int i = 0; i < response.length(); i++ ){
                try{
                    JSONObject obj = response.getJSONObject( i );
                    News news = new News();
                     if( "1".equals( obj.getString( "news_visible" )) ){

                        news.setNews_id( obj.getString( "news_id" ) );
                        news.setNews_title( obj.getString( "news_title" ) );
                        news.setNews_abstract( obj.getString( "news_abstract" ) );
                        news.setNews_content( obj.getString( "news_content" ) );
                        news.setNews_date( obj.getString( "news_date" ) );
                        news.setNews_link( obj.getString( "news_link" ) );
                        news.setNews_image_link( obj.getString( "news_image_link" ));
                        news.setSources_name( obj.getString( "sources_name" ) );
                        news.setCategory_name( obj.getString( "category_name" ) );
                    }
                    newsList.add( news );
                }
                catch( JSONException e ){
                    e.printStackTrace();
                }

解决方案

Content Type

<?PHP
header('Content-Type: application/json');

See Returning JSON from a PHP script.

Byte Order Marker

PHP is prone to return a BOM at the beginning of the response, when the .php file or any of its includes have UTF-8 character encoding.

For more information, see this W3C answer and section UTF-8 BOM in this post.

One suggested way to prevent PHP from prepending a BOM is to change the character set of your php file(s) from UTF-8 to ASCII or ISO-8859-15.

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