java.lang.String类型的值不能转换为JSONArray [英] Value of type java.lang.String cannot be converted to JSONArray

问题描述

我已经花了2天，找到了问题的解决方案。

I've spent 2 days to find a solution with of problem.

下面是错误：

E/log_tag: Error parsing data org.json.JSONException: Value of type java.lang.String cannot be converted to JSONArray

下面是JSON：

[
{
    "Id": "5207fc6473516724343ce7a5",
    "Name": "Эриван",
    "Types": [
        "Ресторан"
    ],
    "Latitude": 53.904752,
    "Longitude": 27.521095,
    "OperatingTime": [
        {
            "Day": 1,
            "Start": "10:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 2,
            "Start": "10:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 3,
            "Start": "10:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 4,
            "Start": "10:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 5,
            "Start": "10:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 6,
            "Start": "08:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 0,
            "Start": "08:00:00",
            "Finish": "23:00:00"
        }
    ],
    "IsBookingAvailable": false
}]

获取字符串值类：

Class for getting String value:

public class JSONGet {

public static String getJSONfromURL(String url){
    InputStream is = null;
    String result = "";
    JSONArray jArray = null;

    // Download JSON data from URL
    try{
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(url);
        HttpResponse response = httpclient.execute(httppost);
        HttpEntity entity = response.getEntity();
        is = entity.getContent();

    }catch(Exception e){
        Log.e("log_tag", "Error in http connection "+e.toString());
    }

    // Convert response to string
    try{
        BufferedReader reader = new BufferedReader(new InputStreamReader(is,"UTF-8"),8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        result = sb.toString();
    }catch(Exception e){
        Log.e("log_tag", "Error converting result "+e.toString());
    }

    try{

        jArray = new JSONArray(result);
    }catch(JSONException e){
        Log.e("log_tag", "Error parsing data "+e.toString());
    }

    return result;
}

}

在这里被转换成JSONArray：

And here is converting to JSONArray:

String jsonObjRecv = JSONGet.getJSONfromURL(URL_LIST);

JSONArray jsonArr = new JSONArray(jsonObjRecv);

我试图让JSON对象，然后将其转换成JSON数组，但我收到了同样的错误。

I was trying to get Json object then convert it into Json array but I received the same error.

推荐答案

现在的问题是，你的JSON是不正确的格式。我曾尝试与样品JSON和找到解决途径。现在，内置的JSONObject和JSONArray不能用来获得这样一个JSON响应。

The problem is that your JSON is in the incorrect format. I have tried with your sample JSON and found the solution to it. Now the inbuilt JSONObject and JSONArray cannot be used to get such a json response.

您需要从以下链接的 HTTPS：//json-simple.google$c$c.com/files/json-simple-1.1.1.jar 。

You need to download a small library named "json-simple-1.1.1.jar" from this link https://json-simple.googlecode.com/files/json-simple-1.1.1.jar.

然后你就可以轻松地分析你的JSON和它不会给任何错误。我已经在做了一个小样本$ C $下你如何使用它：

Then you can parse your JSON easily and it won't give any error. I have made a small sample code for you on how to use it :

import org.json.simple.JSONArray;
import org.json.simple.parser.JSONParser;

JSONParser parser_obj = new JSONParser();
JSONArray array_obj = (JSONArray) parser_obj.parse("String from web service"); 
// in your case it will be "result" 

然后就可以处理它根据您的需要。

Then you can process it as per your need.

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