在一行中捕获多个异常（块除外） [英] Catch multiple exceptions in one line (except block)

问题描述

我知道我可以做：

try:
    # do something that may fail
except:
    # do this if ANYTHING goes wrong

我也可以这样做： p>

I can also do this:

try:
    # do something that may fail
except IDontLikeYouException:
    # say please
except YouAreTooShortException:
    # stand on a ladder

但是，如果我想做同样的事情在两个不同的例外，最好的我现在可以想到的是这样做：

But if I want to do the same thing inside two different exceptions, the best I can think of right now is to do this:

try:
    # do something that may fail
except IDontLikeYouException:
    # say please
except YouAreBeingMeanException:
    # say please

有没有什么办法可以做这样的事情（因为采取这两个例外的行动是说请 ）：

Is there any way that I can do something like this (since the action to take in both exceptions is to say please):

try:
    # do something that may fail
except IDontLikeYouException, YouAreBeingMeanException:
    # say please

现在这真的不行，因为它匹配的语法：

Now this really won't work, as it matches the syntax for:

try:
    # do something that may fail
except Exception, e:
    # say please

所以，我努力捕捉两个不同的例外并不完全

So, my effort to catch the two distinct exceptions doesn't exactly come through.

有没有办法这样做？

推荐答案

从 Python文档：

一个except子句可以将多个异常称为括号元组，例如

An except clause may name multiple exceptions as a parenthesized tuple, for example

except (IDontLikeYouException, YouAreBeingMeanException) as e:
    pass

使用逗号将异常与变量分开仍然适用于Python 2.6和2.7，但现在已被弃用在Python 3中不起作用现在你应该使用作为。

Separating the exception from the variable with a comma will still work in Python 2.6 and 2.7, but is now deprecated and does not work in Python 3; now you should be using as.

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