在一个catch块中捕获多个异常类型 [英] Catching multiple exception types in one catch block

问题描述

我想要一个更干净的方式来获取以下功能，在一个块中捕获 AError 和 BError ：

I'd like a cleaner way to obtain the following functionality, to catch AError and BError in one block:

try
{
    /* something */
}
catch( AError, BError $e )
{
    handler1( $e )
}
catch( Exception $e )
{
    handler2( $e )
}

有什么办法吗？或者我必须分别抓住它们？

Is there any way to do this? Or do I have to catch them separately?

AError 和 Berror 有一个共享的基类，但它们也与其他类型共享，我想通过 handler2 ，所以我不能只是抓住基地

AError and Berror have a shared base class, but they also share it with other types that I'd like to fall through to handler2, so I can't just catch the base class.

推荐答案

如果您可以修改例外情况，使用这个答案。

If you can modify the exceptions, use this answer.

如果你不能，你可以尝试用 Exception 然后检查使用 instanceof 。

If you can't, you could try catching all with Exception and then check which exception was thrown with instanceof.

try
{
    /* something */
}
catch( Exception $e )
{
    if ($e instanceof AError OR $e instanceof BError) {
       // It's either an A or B exception.
    } else {
        // Keep throwing it.
        throw $e;
    }
}

但是更好地使用上述答案中所述的多个catch块。

try
{
    /* something */
}
catch( AError $e )
{
   handler1( $e );
}
catch ( BError $b )
{
   handler2( $e );
}

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