catch块中抛出异常 - 会被再次捕获吗？ [英] Exception thrown inside catch block - will it be caught again?

问题描述

这可能看起来像一个编程101问题，我以为我知道答案，但现在发现自己需要仔细检查。在下面这段代码中，第一个catch块中抛出的异常会被下面的一般异常catch块捕获？

 尝试{
 //做某事
} catch（IOException e）{
 throw new ApplicationException（连接到服务器时出现问题）; 
} catch（Exception e）{
 //将在此处捕获ApplicationException？ 
} 
  

我一直认为答案是否定的，但现在我有一些奇怪的行为这可能是由此造成的。对于大多数语言，答案可能是一样的，但我正在使用Java。

解决方案

不，因为新的 throw 不直接在 try 块中。

This may seem like a programming 101 question and I had thought I knew the answer but now find myself needing to double check. In this piece of code below, will the exception thrown in the first catch block then be caught by the general Exception catch block below?

try {
  // Do something
} catch(IOException e) {
  throw new ApplicationException("Problem connecting to server");
} catch(Exception e) {
  // Will the ApplicationException be caught here?
}

I always thought the answer would be no, but now I have some odd behaviour that could be caused by this. The answer is probably the same for most languages but I'm working in Java.

解决方案

No, since the new throw is not in the try block directly.

这篇关于catch块中抛出异常 - 会被再次捕获吗？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！