在 catch 块内抛出异常 - 会再次被捕获吗? [英] Exception thrown inside catch block - will it be caught again?

问题描述

这似乎是一个编程 101 问题，我以为我知道答案，但现在发现自己需要仔细检查.在下面这段代码中，第一个catch块中抛出的异常会被下面的通用Exception catch块捕获吗?

This may seem like a programming 101 question and I had thought I knew the answer but now find myself needing to double check. In this piece of code below, will the exception thrown in the first catch block then be caught by the general Exception catch block below?

try {
  // Do something
} catch(IOException e) {
  throw new ApplicationException("Problem connecting to server");
} catch(Exception e) {
  // Will the ApplicationException be caught here?
}

我一直认为答案是否定的，但现在我有一些可能由此引起的奇怪行为.大多数语言的答案可能相同，但我使用的是 Java.

I always thought the answer would be no, but now I have some odd behaviour that could be caused by this. The answer is probably the same for most languages but I'm working in Java.

推荐答案

否，因为新的 throw 不直接在 try 块中.

No, since the new throw is not in the try block directly.

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