在被捕获的异常中抛出 [英] Break at throw for exception that is caught

问题描述

在VS调试器中，未捕获的异常会导致程序在异常抛出（或足够接近）时断开，并且处于允许您查看所有堆栈帧的状态，并且存在直到该位置的局部变量

有没有办法获得相同的结果（break in throw），但是异常被捕获在特定的点？我没有兴趣为所有的例外，甚至所有的例外，甚至所有的异常（这可能会变得无用的真正快速）这样做，但如果我可以做一个单一的尝试或catch块我会开心

有些相关：

• 如何解决抛出时间（每个类和我正在寻找每个try / catch块）

解决方案

调试 - >例外对话框是否执行您想要的？您可以选择哪些异常会导致VS断开，无论它们是否被捕获。我不知道只有一部分代码才能执行此操作，只能根据引发的异常类型。

In the VS debugger, un-caught exceptions result in the program breaking at the point the exception is throw (or near enough) and in a state that lets you look at all the stack frames and there local variables up to that point.

Is there a way to get this same result (break at throw) but for an exception is caught at a particular point? I'm not interested in doing this for ALL exceptions or even all exception of a given type (that could get useless real quick) but if I could do it for a single try or catch block I'd be happy

somewhat related:

• How to work around ‘Break when thrown’ (Is per class and I'm looking for per try/catch block)

解决方案

Does the Debug -> Exceptions dialog do what you want? You can select which Exceptions that will cause VS to break, regardless of whether they are caught or not. I don't know of a way to do this for only a certain part of the code, only based on the type of the exception thrown.

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