Mockito如何模拟和断言抛出异常? [英] Mockito How to mock and assert a thrown exception?
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问题描述
解决方案
BDD 样式解决方案
Mockito 独自一人不是处理异常的最佳解决方案,使用 Mockito 与 Catch-Exception
Mockito + Catch-Exception + AssertJ
给定(otherServiceMock.bar())。willThrow(new MyException ());
当(myService).foo();
then(caughtException())。isInstanceOf(MyException.class);
示例代码
依赖关系
- eu.codearte.catch-exception:catch-exception:1.3 .3
- org.assertj:assertj-core:1.7.0
Disadvantage
- 仅支持1.10.8的Mockito
I'm using mockito in a junit test. How do you make an exception happen and then assert that it has (generic pseudo-code)
解决方案
BDD Style Solution
Mockito alone is not the best solution for handling exceptions, use Mockito with Catch-Exception
Mockito + Catch-Exception + AssertJ
given(otherServiceMock.bar()).willThrow(new MyException());
when(myService).foo();
then(caughtException()).isInstanceOf(MyException.class);
Sample code
Dependencies
- eu.codearte.catch-exception:catch-exception:1.3.3
- org.assertj:assertj-core:1.7.0
Disadvantage
- Only Mockito up to 1.10.8 is supported
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