尝试使用 mockito 抛出检查异常的问题 [英] Issues trying throw checked exception with mockito

问题描述

我有下面的界面

public interface Interface1 {
    Object Execute(String commandToExecute) throws Exception;
}

然后我试图模拟它以便我可以测试将调用它的类的行为:

which then I 'm trying to mock so I can test the behaviour of the class that will call it:

Interface1 interfaceMocked = mock(Interface1.class);
when(interfaceMocked.Execute(anyString())).thenThrow(new Exception());
Interface2 objectToTest = new ClassOfInterface2(interfaceMocked);
retrievePrintersMetaData.Retrieve();

但是编译器告诉我有一个未处理的异常.Retrieve 方法的定义是:

But the compiler tells me that there is an unhandled exception. The definition of the Retrieve method is:

public List<SomeClass> Retrieve() {
    try {
        interface1Object.Execute("");
    }
    catch (Exception exception) {
        return new ArrayList<SomeClass>();
    }
}

mockito 文档只展示了 RuntimeException 的使用，我在 StackOverflow 上没有看到类似的东西.我使用的是 Java 1.7u25 和 mockito 1.9.5

The mockito documentation only shows uses of RuntimeException, and I have not seen anything on similar on StackOverflow. I'm using Java 1.7u25 and mockito 1.9.5

推荐答案

假设你的测试方法没有声明它抛出 Exception，编译器是绝对正确的.这一行:

Assuming your test method doesn't declare that it throws Exception, the compiler's absolutely right. This line:

when(interfaceMocked.Execute(anyString())).thenThrow(new Exception());

... 对 Interface1 的实例调用 Execute.那可能会抛出Exception，所以你要么需要捕获它，要么声明你的方法抛出它.

... calls Execute on an instance of Interface1. That can throw Exception, so you either need to catch it or declare that your method throws it.

我个人建议只声明测试方法抛出Exception.没有其他人会关心那个声明，你真的不想抓住它.

I would personally recommend just declaring that the test method throws Exception. Nothing else will care about that declaration, and you really don't want to catch it.

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