单独的文件路由在快递 [英] separate file for routes in express

问题描述

我想知道如何将我的快递中的所有api路由从我的 server.js 中单独的 routes.js code>文件

I was wondering how do I move all of my api routes in express into a separate routes.js file from my server.js file

我有一个很长的api路线，使用 app.use（）路线。所以每个路由都在自己的文件中，例如 movies.js ， movie.js 但是当我列出这些，它使一个长列表在 server.js

I have a long list of api routes using app.use() for each route. So each route is in its own file, e.g. movies.js, movie.js but when I list these it makes for a long list in server.js

所以我想从下面的 server.js中删除api端点列表/ code> out to a routes.js file。

So I want to remove the list of api endpoints section from the below server.js out to a routes.js file.

这是我目前所在：

server.js

server.js

import path from 'path'
import express from 'express'
import webpack from 'webpack'
import webpackDevMiddleware from 'webpack-dev-middleware'
import webpackConfig from './webpack.config.dev'

const app = express();

/* api endpoints, can be many more, I want them in routes.js */    
app.use('/api/movies', require('./src/api/routes/movies'))
app.use('/api/movie', require('./src/api/routes/movie'))

app.use(webpackDevMiddleware(webpack(webpackConfig), {
  publicPath: webpackConfig.output.publicPath
}));

app.use('/public', express.static(__dirname + '/public'))    

app.get('*', function(req, res) {
  res.sendFile(path.join(__dirname, 'index.html'));
});


app.listen(3000, 'localhost', function (err) {
  if (err) {
    console.log(err);
    return;
  }
})

示例路由

movies.js

var express = require('express');
var request = require("request");
var router = express.Router();

router.get('/', function(req, res) {
  res.json({})
});

module.exports = router;

推荐答案

您可以尝试使用以下模块化方法。
定义具有每个功能逻辑的控制器文件。例如电影。

You can try to use the following modular approach. Define controller files having logic per feature. e.g. movie.

movieController.js

module.exports = {
    getMovie : function(req, res){
       //do something
    },
    getMovies : function(req, res){
       //do something
    },
    postMovie : function(req, res){
       //do something
    }
}

然后，在路由文件中引用该控制器，并简单地插入这些功能。

Then, reference that controller in routes files and simply plug those functions.

route.js

var express = require('express');
var movieCtrl = require('./movieController');

var router = express.Router();

router.route('/movie').get(movieCtrl.getMovie);
router.route('/movie').post(movieCtrl.postMovie);
router.route('/movies').get(movieCtrl.getMovies);

module.exports = router;

而且，在app.js中，将路由安装到合适的位置，例如/ api

And, in app.js, mount the routes to suitable location, e.g. /api

app.js

var routes = require('./routes');
app.use('/api', routes);

这篇关于单独的文件路由在快递的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！