如何使用NodeJS和Express从app.js中分离路由和模型 [英] How to separate the routes and models from app.js using NodeJS and Express

问题描述

我正在使用Node和Express创建一个应用程序。但是，我可以看到很快就会很难管理放在 app.js 内的所有路由。我把所有的模型放在子目录 / models 中。

这是我的应用程序当前结构：

  app.js 
模型
  - 产品
  - 客户
  -  .. 。
 public 
查看
 node_modules 
  

在 app.js ：

  var express = require（'express'），
 routes = require（'./ routes'），
 user = require（'./ routes / user'），
 http = require（'http'），
 path = 'path'），
 EmployeeProvider = require（'./ models / employeeprovider'）。EmployeeProvider，
产品= require（'./ models / products'）。产品，
订单= require （'./models/orders').Orders，
 Customer = require（'./ models / customers'）。客户
 checkAuth = function（req，res，next）{
 if（！req.session.user_id）{
 res.send（'你无权查看此页面'）; 
} else {
 next（）; 
} 
}; 
 
 var app = express（）; 
  

然后一些配置，如 port ，视图目录，渲染引擎等。

进一步向下 app.js 我有路线：

  app.get（'/ product / edit'，auth，function（req， res）{
 Products.findAll（function（error，prds）{
 res.render（'product_edit'，{
 title：'New Product'，
 products：prds 
}）; 
}）; 
}）; 
  

在顶部我分配了 models / products.js的内容到一个变量，一切正常。但是，将所有路线保持在 app.js 之内并不理想。但是如果我将路线移动到 routes / product.js 并加载产品型号：

  var prod = require（'../ models / products.js'）; 
  

我收到一个错误，表示该对象没有方法 findAll 。

我做错了什么？如何从 app.js 中删除​​路线？

解决方案

As的快递4.x 路由器被添加以支持您的情况。

路由器对象是中间件和路由的孤立实例。您可以将其视为微型应用程序，只能执行中间件和路由功能。每个Express应用程序都有一个内置的应用路由器。

expressjs网站：

  // routes / calendarRouter.js 
 
 var express = require（'express'）; 
 var router = express.Router（）; 
 
 //为任何请求传递给该路由器
 router.use（function（req，res，next）{
 // ..这里有一些逻辑..像任何其他中间件
 next（）; 
}）; 
 
 //将处理结束于/ events 
 //的任何请求取决于路由器在哪里use（）d
 router.get（'/ events' ，function（req，res，next）{
 // .. 
}）; 
 
 module.exports = router; 
  

然后在app.js中：

  //跳过部分设置app 
 
 var calendarRouter = require（'./ routes / calendarRouter'）; 
 
 //只有/ calendar / *的请求将被发送到我们的路由器
 app.use（'/ calendar'，calendarRouter）; 
 
 //其余逻辑
  

I'm creating an app using Node and Express. However, I can see it'll soon become difficult to manage all the routes that are placed inside app.js. I have placed all my models in a subdirectory /models.

Here's my app current structure:

app.js
models
  -- products
  -- customers
  -- ...
public
views
node_modules

In app.js:

var express = require('express'),
    routes = require('./routes'),
    user = require('./routes/user'),
    http = require('http'),
    path = require('path'),
    EmployeeProvider = require('./models/employeeprovider').EmployeeProvider,
    Products = require('./models/products').Products,
    Orders = require('./models/orders').Orders,
    Customers = require('./models/customers').Customers,
    checkAuth = function(req, res, next) {
      if (!req.session.user_id) {
        res.send('You are not authorized to view this page');
      } else {
        next();
      }
    };

var app = express();

Then some configuration like port, views directory, rendering engine, etc.

Further down app.js I've got the routes:

app.get('/product/edit', auth, function(req, res) {
  Products.findAll(function(error, prds) {
    res.render('product_edit', {
      title: 'New Product',
      products: prds
    });
  });
});

At the top I'm assigning the contents of models/products.js to a variable, all works fine. However keeping all routes inside app.js is not ideal. But if I move the routes to routes/product.js and load the Products models:

var prod = require('../models/products.js');

I get an error saying that object has no method findAll.

What am I doing wrong? How can I remove the routes from app.js?

解决方案

As of express 4.x Router is added to support your case.

A router object is an isolated instance of middleware and routes. You can think of it as a "mini-application," capable only of performing middleware and routing functions. Every Express application has a built-in app router.

Example from expressjs site:

// routes/calendarRouter.js

var express  = require('express');
var router = express.Router();

// invoked for any requested passed to this router
router.use(function(req, res, next) {
  // .. some logic here .. like any other middleware
  next();
});

// will handle any request that ends in /events
// depends on where the router is "use()'d"
router.get('/events', function(req, res, next) {
  // ..
});

module.exports = router;

Then in app.js:

// skipping part that sets up app

var calendarRouter = require('./routes/calendarRouter');

// only requests to /calendar/* will be sent to our "router"
app.use('/calendar', calendarRouter);

// rest of logic

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