json api图调用不返回任何东西? [英] json api graph call does not return anything?

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本文介绍了json api图调用不返回任何东西?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在获取用户fb newfeed,我想得到检查wether用户喜欢的帖子或不使用user_likes,问题是以下代码不会返回任何东西:

i am fetching users fb newfeed and i wanted get check wether user has liked the post or not by using user_likes and the problem is that the following code wont return anything :

$getlike = $facebook->api("/fql?q=SELECT like_info FROM stream WHERE post_id=" . $id);
$checklike = $getlike['data'][0]['like_info']['user_likes'];

这是完整的文件: testone.php
的问题是,fql和调用user_likes不会返回任何东西。
i想检查wether用户已经喜欢的帖子已经 OR 如何获取user_likes的值。

here is the complete file: testone.php the problem is that the fql and calling user_likes wont return anything. i want to check wether user has liked the post already OR how can i get the value for user_likes.

从fb的JSON:

JSON from fb :

{
  "data": [
    {
      "like_info": {
        "can_like": true, 
        "like_count": 70, 
        "user_likes": false
      }
    }
  ]
}

我的技术是否正确?我需要访问代码吗?

is my technique right?do i need access code or something?

推荐答案

如果您获得 $ getlike 的值,则可以检查 user_likes的值这样(因为它是类型boolean) -

If you are getting the value of $getlike, you can check the value of user_likes like this (since it is of type boolean)-

if($getlike['data'][0]['like_info']['user_likes'])
{
    echo "true";    
}
else 
{
    echo "false";   
}

这篇关于json api图调用不返回任何东西?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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