在node.js中获取上传的文件名/路径 [英] get uploaded file name/path in node.js

问题描述

如何获取上传的文件名/路径的名称以在node.js中操作它？我想将文件从临时文件夹移动到客户文件夹。

解决方案

Node.JS不会自动将上传的文件保存到磁盘。您将不得不通过 multipart / form-data 内容#http_class_http_serverrequestrel =nofollow noreferrer> request 的 data 和 end 事件。也可以使用一个库来完成所有的工作，比如 connect / express 其 bodyParser 或 multipart 中间件（完整示例）：

  var fs = require（'fs'）; 
 var express = require（'express'）; 
 var app = express（）; 
 
 //`bodyParser`包含`multipart` 
 app.use（express.bodyParser（））; 
 
 app.post（'/'，function（req，res，next）{
 //假设< input type =filename =upload> 
 
 var path = req.files.upload.path; 
 var name = req.files.upload.name; 
 
 // copy ... 
} ）; 
  

或者使用 formidable ， connect 用于 multipart 中间件（ complete例如）。

而对于 // copy ... 评论，请参阅如何复制文件？。

How do I get the name of an uploaded file name/path to manipulate it in node.js? I want move the file from the temp folder to a customer folder.

解决方案

Node.JS doesn't automatically save uploaded files to disk. You'll instead have to read and parse the multipart/form-data content yourself via the request's data and end events.

Or, you can use a library to do that all for you, such as connect/express for its bodyParser or multipart middlewares (complete example):

var fs = require('fs');
var express = require('express');
var app = express();

// `bodyParser` includes `multipart`
app.use(express.bodyParser());

app.post('/', function(req, res, next){
  // assuming <input type="file" name="upload">

  var path = req.files.upload.path;
  var name = req.files.upload.name;

  // copy...
});

Or use formidable directly, which connect uses for the multipart middleware (complete example).

And, for the // copy... comment, see How to copy a file?.

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