在Java中检测符号链接 [英] Detecting a symlink in Java

问题描述

给定一个Java的文件对象，我该如何检测它是否引用符号链接？

（如果有帮助/重要，我知道文件指的是一个目录，而不是一个文件）

解决方案

File.getCanonicalPath（） 解析符号链接

规范的路径名既是绝对路径，也是唯一的。规范形式的确切定义是依赖于系统的。如果需要，此方法首先将此路径名转换为绝对形式，就像调用getAbsolutePath（）方法一样，然后以依赖于系统的方式将其映射到其唯一形式。这通常涉及删除多余的名称，如。和..，解析符号链接（在UNIX平台上），并将驱动器号转换为标准大小写（在Microsoft Windows平台上）。

我假设您可以比较 getCanonicalPath（）和 getAbsolutePath（）。

更新：看来这个问题已经被问到了 - 检查答案

Given a Java 'File' object, how can I detect whether or not it refers to a symlink?

(If it helps/matters, I know the file refers to a directory, not to a file)

解决方案

File.getCanonicalPath() resolves symlinks

A canonical pathname is both absolute and unique. The precise definition of canonical form is system-dependent. This method first converts this pathname to absolute form if necessary, as if by invoking the getAbsolutePath() method, and then maps it to its unique form in a system-dependent way. This typically involves removing redundant names such as "." and ".." from the pathname, resolving symbolic links (on UNIX platforms), and converting drive letters to a standard case (on Microsoft Windows platforms).

I assume you can compare the result of getCanonicalPath() and getAbsolutePath().

Update: It appears this question has already been asked - check the answers there

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