跨平台方式检测符号链接/连接点？ [英] Cross platform way to detect a symbolic link / junction point?

问题描述

在java中，可以通过比较文件的规范路径和绝对路径来检测Unix环境中的符号链接。但是，这个技巧在Windows上不起作用。如果我执行

In java, a symbolic link in a Unix environment can be detected by comparing the file's canonical and absolute path. However, this trick does not work on windows. If I execute

mkdir c:\foo
mklink /j c:\bar

然后在java中执行以下行

from the command line and then execute the following lines in java

File f = new File("C:/bar");
System.out.println(f.getAbsolutePath());
System.out.println(f.getCanonicalPath());

输出

C:\bar
C:\bar

是有没有在Java中检测结点的Java前方法？

Is there any pre-Java 7 way of detecting a junction in windows?

推荐答案

似乎没有任何跨平台机制对于Java 6或更早版本中的这个，虽然它是一个使用JNA的相当简单的任务

There doesn't appear to be any cross platform mechanism for this in Java 6 or earlier, though its a fairly simple task using JNA

interface Kernel32 extends Library {
  public int GetFileAttributesW(WString fileName);
}

static Kernel32 lib = null;
public static int getWin32FileAttributes(File f) throws IOException { 
  if (lib == null) {
    synchronized (Kernel32.class) {
      lib = (Kernel32) Native.loadLibrary("kernel32", Kernel32.class);
    }
  }
  return lib.GetFileAttributesW(new WString(f.getCanonicalPath()));
}

public static boolean isJunctionOrSymlink(File f) throws IOException {
  if (!f.exists()) { return false; }
  int attributes = getWin32FileAttributes(f);
  if (-1 == attributes) { return false; }
  return ((0x400 & attributes) != 0);
}

编辑：根据的可能错误返回的每条评论更新getWin32FileAttributes（）

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