PHP的 - 上传文件到另一台服务器没有卷曲 [英] PHP - Upload file to another server without curl

问题描述

我有一个问题，我可以上传文件到另一台服务器，而不卷曲..
因为不是每个服务器都有卷曲...
谢谢...

http://php.net $ man
$ b

  function do_post_request（$ url，/ manual / en / function.stream-context-create.php ） $ postdata，$ files = null）
 {
 $ data =; 
 $ boundary =---------------------。substr（md5（rand（0,32000）），0，10）; 
 
 //收集Postdata 
 foreach（$ postdata as $ key => $ val）
 {
 $ data。= -  $ boundary \\\
 ; 
 $ data。=Content-Disposition：form-data; name = \。$ key。\\\\
\\\
。$ val。\\\
; 
} 
 
 $ data。= -  $ boundary \\\
; 
 
 //收集Filedata 
 foreach（$文件为$ key => $文件）
 {
 $ fileContents = file_get_contents（$ file ['tmp_name'] ）; 
 $ b $ data。=Content-Disposition：form-data; name = \{$ key} \; filename = \{$ file ['name']} \ \\\
; 
 $ data。=Content-Type：image / jpeg\\\
; 
 $ data。=Content-Transfer-Encoding：binary \\\
\\\
; 
 $ data。= $ fileContents。\\\
; 
 $ data。= -  $ boundary  -  \\\
; 
 
 $ b $ params = array（'http'=> array（
'method'=>'POST'，
'header'=> 'Content-Type：multipart / form-data; boundary ='。$ boundary，
'content'=> $ data 
））; 
 
 $ ctx = stream_context_create（$ params）; 
 $ fp = fopen（$ url，'rb'，false，$ ctx）; 
 
 if（！$ fp）{
抛出新的异常（带有$ url的问题，$ php_errormsg）; 
} 
 
 $ response = @stream_get_contents（$ fp）; 
 if（$ response === false）{
抛出新的异常（从$ url读取数据的问题，$ php_errormsg）; 
} 
返回$ response; 
 
 
 //设置数据（在这个例子中是帖子）
 
 //样本数据
 $ postdata =数组（
' name'=> $ _POST ['name']，
'age'=> $ _POST ['age']，
'sex'=> $ _POST ['sex'] 
）; 
 
 //示例图片
 $文件['image'] = $ _FILES ['image']; 
 
 do_post_request（http://example.com，$ postdata，$ files）; 
  

I have one question, can i upload file to another server without curl.. Because not every server have CURL ... Thanks...

解决方案

Yes it is possible using pure PHP fopen together with stream_context_create. The following example comes from the online PHP manual (http://php.net/manual/en/function.stream-context-create.php):

function do_post_request($url, $postdata, $files = null) 
{ 
    $data = ""; 
    $boundary = "---------------------".substr(md5(rand(0,32000)), 0, 10); 

    //Collect Postdata 
    foreach($postdata as $key => $val) 
    { 
        $data .= "--$boundary\n"; 
        $data .= "Content-Disposition: form-data; name=\"".$key."\"\n\n".$val."\n"; 
    } 

    $data .= "--$boundary\n"; 

    //Collect Filedata 
    foreach($files as $key => $file) 
    { 
        $fileContents = file_get_contents($file['tmp_name']); 

        $data .= "Content-Disposition: form-data; name=\"{$key}\"; filename=\"{$file['name']}\"\n"; 
        $data .= "Content-Type: image/jpeg\n"; 
        $data .= "Content-Transfer-Encoding: binary\n\n"; 
        $data .= $fileContents."\n"; 
        $data .= "--$boundary--\n"; 
    } 

    $params = array('http' => array( 
           'method' => 'POST', 
           'header' => 'Content-Type: multipart/form-data; boundary='.$boundary, 
           'content' => $data 
        )); 

   $ctx = stream_context_create($params); 
   $fp = fopen($url, 'rb', false, $ctx); 

   if (!$fp) { 
      throw new Exception("Problem with $url, $php_errormsg"); 
   } 

   $response = @stream_get_contents($fp); 
   if ($response === false) { 
      throw new Exception("Problem reading data from $url, $php_errormsg"); 
   } 
   return $response; 
} 

//set data (in this example from post) 

//sample data 
$postdata = array( 
    'name' => $_POST['name'], 
    'age' => $_POST['age'], 
    'sex' => $_POST['sex'] 
); 

//sample image 
$files['image'] = $_FILES['image']; 

do_post_request("http://example.com", $postdata, $files); 

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