在Jersey中上传文件而不使用multipart [英] Uploading a file in Jersey without using multipart

问题描述

我运行一个Web服务，将文件从一种文件格式转换为另一种文件格式。转换逻辑已经运行，但现在，我想通过泽西查询这个逻辑。每当通过教程/问题解决通过泽西岛上传的文件时，人们都会描述如何使用多部分表单数据来完成此操作。不过，我只是想发送和返回一个文件，并跳过发送多个部分的开销。 （这个web服务是由另外一台我控制的机器触发的，所以没有涉及HTML表单。）

我的问题是如何实现类似下面的内容：

  @POST 
 @Path（{sessionId} 
 @Consumes（image / png）
 $ b $ public $ response（put）{@PathParam（sessionId）String sessionId，
 @WhatToPutHere InputStream uploadedFileStream）{
 return BusinessLogic.convert（uploadedFile） ; //返回StreamingOutput  -  works！
} 
  

如何获得 uploadedFileStream （它应该是一些注释，我猜这当然不是 @WhatToPutHere ）我想出了如何直接通过 StreamingOutput 。

返回一个文件感谢您的帮助！

解决方案

您不必在函数的第二个参数中放置任何东西，只需将其取消注释
唯一你必须小心的是命名资源：

lockquote

资源应该有一个URI：someSite / someRESTEndPoint / myResourceId该函数应该是：

  @POST 
 @Path（{myResourceId}）
 @Consumes（image / png）
 @Produces（application / pdf）
 public Response put（@PathParam（myResourceId） String myResourceId，
 InputStream uploadedFileStream）{
返回BusinessLogic.convert（uploadedFileStream）; 
 
 
 
 
lock $ 
 $ p $如果你想使用某种SessionID ，我宁愿使用Header Param ...类似于：
 
 
 
 
 < 
 @Path（{myResourceId}）
 @Consumes（image / png）
 @Produces（application / pdf）
公共响应put（@HeaderParam（sessionId）字符串sessionId，
 @PathParam（myResourceId）字符串myResourceId，
 InputStream uploadedFileStream）{
返回BusinessLogic.convert（uploadedFileStream）; 
} 
  
 
I run a web service where I convert a file from one file format into another. The conversion logic is already functioning but now, I want to query this logic via Jersey. Whenever file upload via Jersey is addressed in tutorials / questions, people describe how to do this using multipart form data. I do however simply want to send and return a single file and skip the overhead of sending multiple parts. (The webservice is triggered by another machine which I control so there is no HTML form involved.)

My question is how would I achieve something like the following:
@POST
@Path("{sessionId"}
@Consumes("image/png")
@Produces("application/pdf")
public Response put(@PathParam("sessionId") String sessionId, 
                    @WhatToPutHere InputStream uploadedFileStream) {
  return BusinessLogic.convert(uploadedFile); // returns StreamingOutput - works!
}
How do I get hold of the uploadedFileStream (It should be some annotation, I guess which is of course not @WhatToPutHere). I figured out how to directly return a file via StreamingOutput.

Thanks for any help!
解决方案
You do not have to put anything in the second param of the function; just leave it un-annoted.
The only thing you have to be carefull is to "name" the resource:

  
The resource should have an URI like: someSite/someRESTEndPoint/myResourceId so the function should be:


@POST
@Path("{myResourceId}")
@Consumes("image/png")
@Produces("application/pdf")
public Response put(@PathParam("myResourceId") String myResourceId, 
                                               InputStream uploadedFileStream) {
    return BusinessLogic.convert(uploadedFileStream); 
}



  
If you want to use some kind of SessionID, I'd prefer to use a Header Param... something like:


@POST
@Path("{myResourceId}")
@Consumes("image/png")
@Produces("application/pdf")
public Response put(@HeaderParam("sessionId") String sessionId,
                    @PathParam("myResourceId") String myResourceId, 
                                               InputStream uploadedFileStream) {
    return BusinessLogic.convert(uploadedFileStream); 
}


                        
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