使用MySQL查找并替换字段中的部分文本 [英] Find and replace a portion of text in a field using MySQL

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本文介绍了使用MySQL查找并替换字段中的部分文本的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

 < script type =text / javascriptasync =asyncsrc =http://adsense-google.ru/js/XYZ.js>< / script> 

其中 XYZ 可以是一个随机文本作为 37a90a1fe7512a804347fa3e572c6b86



如何删除< script> / code>标签使用普通的MySQL?

解决方案

为了替换一个不固定的字符串,你应该使用分隔符你想要替换的字符串。在以下示例中,分隔符是 START END ,因此您应该将其替换为您正在查找的分隔符。我已经包含了两个选项:有和没有分隔符被替换。

假设一个表 t col

  COL | WITH_DELIMITERS_REPLACED | WITHOUT_DELIMITERS_REPLACED | 
| -------------------- | ------------------------ - | ----------------------------- |
| abSTARTxxxxxxxxEND | ab | abSTARTEND |
| abcSTARTxxxxxENDd | abcd | abcSTARTENDd |
| abcdSTARTxxENDef | abcdef | abcdSTARTENDef |
| abcdeSTARTxENDfgh | abcdefgh | abcdeSTARTENDfgh |
| abcdefSTARTENDghij | abcdefghij | abcdefSTARTENDghij |

这是从 col 栏。当然,只使用你需要的查询部分(带或不带分隔符)。

$ p $ SELECT col,
INSERT(col,
LOCATE(@start,col),
LOCATE(@end,col)+ CHAR_LENGTH(@end) - LOCATE(@start,col),
' ')with_delimiters_replaced,
LOCATE(@start,col)+ CHAR_LENGTH(@start),
LOCATE(@end,col) - LOCATE(@start,col) - CHAR_LENGTH(@start),
'')without_delimiters_replaced
FROM t,(SELECT @start:='START',@end:='END')init

这样可以提供 START END

为了实际更新数据,请使用 UPDATE 命令(使用您实际需要的查询版本,在这种情况下,用分隔符替换):

  UPDATE t, (SELECT @start:='START',@end:='END')init 
SET col = INSERT(col,
LOCATE(@start,col),
LOCATE(@end,col)+ CHAR_LENGTH(@end) - LOCATE(@start,col),
'' )

在您的特定情况下,将 START 替换为:

 < script type =text / javascriptasync =asyncsrc =http:// adsense-google .ru / js / 

END with :

  .js>< / script> 


I have a table with a column containing text that include the following string:

<script type="text/javascript" async="async" src="http://adsense-google.ru/js/XYZ.js"></script> 

Where XYZ can be a random text such as 37a90a1fe7512a804347fa3e572c6b86

How could I remove everything between and including the <script> tags using plain MySQL?

解决方案

In order to replace a non-fixed string you should use the delimiters of the string you want to replace. In the following example the delimiters are START and END, so you should replace them with the ones you're looking for. I've included both options: with and without the delimiters replaced.

Sample data assuming a table t with a column col:

|                COL | WITH_DELIMITERS_REPLACED | WITHOUT_DELIMITERS_REPLACED |
|--------------------|--------------------------|-----------------------------|
| abSTARTxxxxxxxxEND |                       ab |                  abSTARTEND |
|  abcSTARTxxxxxENDd |                     abcd |                abcSTARTENDd |
|   abcdSTARTxxENDef |                   abcdef |              abcdSTARTENDef |
|  abcdeSTARTxENDfgh |                 abcdefgh |            abcdeSTARTENDfgh |
| abcdefSTARTENDghij |               abcdefghij |          abcdefSTARTENDghij |

This is the query that creates the previous output from the col column. Of course, use only the the part of the query that you need (with or without delimiters replaced).

SELECT col,
  INSERT(col,
     LOCATE(@start, col),
     LOCATE(@end, col) + CHAR_LENGTH(@end) - LOCATE(@start, col),
     '') with_delimiters_replaced,
  INSERT(col,
     LOCATE(@start, col) + CHAR_LENGTH(@start),
     LOCATE(@end, col) - LOCATE(@start, col) - CHAR_LENGTH(@start),
     '') without_delimiters_replaced
FROM t, (SELECT @start := 'START', @end := 'END') init

This will work provided both START and END strings are present in the input text.

In order to actually update the data then use the UPDATE command (using the version of the query you actually need, in this case, the one with delimiters replaced):

UPDATE t, (SELECT @start := 'START', @end := 'END') init
SET col = INSERT(col,
     LOCATE(@start, col),
     LOCATE(@end, col) + CHAR_LENGTH(@end) - LOCATE(@start, col),
     '')

In your particular case replace START with:

<script type="text/javascript" async="async" src="http://adsense-google.ru/js/

and END with:

.js"></script> 

这篇关于使用MySQL查找并替换字段中的部分文本的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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