从范围的底部开始,在vba内执行查找 [英] Perform a FIND, within vba, from the bottom of a range up
问题描述
下午好,
Find 是否可以从一个范围的底部开始, ?我想要的是我的代码首先找到一个记录号码,将位于主列表。一旦找到记录号码,我希望它将交易名称(记录号码的一个 offset
)分配给一个变量,然后在主列表中搜索第一个交易那个同名的
目前,我有代码来查找记录号,将交易名分配给一个变量,然后循环每个单元直到找到匹配。虽然这种方式有效,但循环处理时间明显慢于查找处理时间,我正在寻找最快的解决方案。
如果反向查找不可能,那么一个vlookup的工作?有可能通过创建一个范围从记录数上面的第一行开始,并有vlookup找到最后的发生?
任何帮助表示赞赏。
PendingBRow = ThisWorkbook.Sheets(PendingLog)。Range(A65000)。End(xlUp).Row
> FIND() 底部 :
$ MasterBow = ThisWorkbook.Sheets(MasterLog)。Range(A65000)。End(xlUp).Row
For D = 2 To PendingBRow
With ThisWorkbook.Sheets( PendingLog)。Range(A& D)
PendingRecNum = .Value
PendingDealName = .offset(0,3).Value
PDLenght = Len(PendingDealName) - 4
PendingDealName = Left(PendingDealName,PDLenght)
PendingDealName = UCase(PendingDealName)
PendingDealName = Trim(PendingDealName)
End With
With ThisWorkbook.Sheets( (B2:B& MasterBRow)
Set c = .Find(PendingRecNum,LookIn:= xlValues)
如果Not c不是Nothing那么
firstRow = c。行 - 1
O = 1
直到firstRow = O
LastWorkedBy = ThisWorkbook.Sheets(MasterLog)。Range(E& firstRow).off set(0,20)
MasterRecNum = ThisWorkbook.Sheets(MasterLog)。Range(E& firstRow).offset(0,-3).Value
dealName = ThisWorkbook.Sheets(MasterLog)。Range(E& firstRow).Value
dealName = Left(dealName,10)如果PendingDealName = dealName然后
MasterLastWorkedBy = LastWorkedBy
ThisWorkbook.Sheets(PendingLog($) ).Range(A& D).offset(0,19).Value = MasterLastWorkedBy
firstRow = O
else
firstRow = firstRow - 1
End If
Loop
End If
End With
Next D
$ b $ pre $ code $ Sub FindFromTheBottom
Set a = Range(A:A)。Find(Test ,之后:=单元格(1,1), searchdirection:= xlPrevious)
MsgBox a.Address(0,0)
End Sub
Good Afternoon,
Is it possible for Find
to start from the bottom of a range and work up? What I would like is my code to first find a record number that will be located on a master list. Once it finds the record number I want it to assign that deals name, an offset
of the record number, to a variable and then search up the master list for the first deal with that same name.
Currently, I have code that finds the record number, assigns the deal name to a variable and then loop's up each cell until it finds a match. Although this way works, the loop processing time is significantly slower than the find processing time and I am searching for the fastest solution.
If reverse find is not a possibility, would a vlookup work? Possibly by, creating a range beginning 1 row above the record number to the top and have vlookup find the last occurance?
Any help is appreciated.
PendingBRow = ThisWorkbook.Sheets("PendingLog").Range("A65000").End(xlUp).Row
MasterBRow = ThisWorkbook.Sheets("MasterLog").Range("A65000").End(xlUp).Row
For D = 2 To PendingBRow
With ThisWorkbook.Sheets("PendingLog").Range("A" & D)
PendingRecNum = .Value
PendingDealName = .offset(0, 3).Value
PDLenght = Len(PendingDealName) - 4
PendingDealName = Left(PendingDealName, PDLenght)
PendingDealName = UCase(PendingDealName)
PendingDealName = Trim(PendingDealName)
End With
With ThisWorkbook.Sheets("MasterLog").Range("B2:B" & MasterBRow)
Set c = .Find(PendingRecNum, LookIn:=xlValues)
If Not c Is Nothing Then
firstRow = c.Row - 1
O = 1
Do Until firstRow = O
LastWorkedBy = ThisWorkbook.Sheets("MasterLog").Range("E" & firstRow).offset(0, 20)
MasterRecNum = ThisWorkbook.Sheets("MasterLog").Range("E" & firstRow).offset(0, -3).Value
dealName = ThisWorkbook.Sheets("MasterLog").Range("E" & firstRow).Value
dealName = Left(dealName, 10)
dealName = UCase(dealName)
dealName = Trim(dealName)
If PendingDealName = dealName Then
MasterLastWorkedBy = LastWorkedBy
ThisWorkbook.Sheets("PendingLog").Range("A" & D).offset(0, 19).Value = MasterLastWorkedBy
firstRow = O
Else
firstRow = firstRow - 1
End If
Loop
End If
End With
Next D
This will FIND() from the bottom:
Sub FindFromTheBottom()
Set a = Range("A:A").Find("Test", after:=Cells(1, 1), searchdirection:=xlPrevious)
MsgBox a.Address(0, 0)
End Sub
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