我怎样才能结合查找命令？ [英] How can I combine the Find-commands?

问题描述

问题出现在我原来的问题这里。 a>

我试图用find命令找到两个find命令的输出之间的公共元素。

pre $ find $ find〜/ bin / FilesDvorak /.* -maxdepth 0` -and` find〜/ .PAST_RC_files /.*`

解决方案

像这样的工作，而不是重新发明轮子？

  diff -qrs〜/ bin / FilesDvorak /〜/ .PAST_RC_files / grep -P是相同的|不同的
  

你可以使用grep来获取文件只有在其中一个dirs等。

差异

$ ul

-q - -brief只输出文件是否有区别。

-r --recursive递归比较找到的所有子目录。

-s --report-identical-files报告两个文件相同。

grep

• -P：Perl风格的正则表达式。但是，如果没有它，也许可以做得很好，我通常会自动添加它。

The question emerged my original question here.

I try to find the common elements between the outputs of the two find-commands with a find-command. How can I get the command working?

find `find ~/bin/FilesDvorak/.* -maxdepth 0` -and `find ~/.PAST_RC_files/.*`

解决方案

Would something like this work instead, rather than reinvent the wheel?

diff -qrs ~/bin/FilesDvorak/ ~/.PAST_RC_files/ | grep -P "are identical|differ"

You can play around with the grep to get the files present only in one of the dirs, etc.

diff

• -q --brief Output only whether files differ.
• -r --recursive Recursively compare any subdirectories found.
• -s --report-identical-files Report when two files are the same.

grep

• -P: Perl style regex. You can probably do away just fine without it though, I usually add it automatically.

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