创建一个正则表达式来找到一个括号的缩写（VBasic Word） [英] Creating a RegEx to find a sentence with a parenthetical acronym (VBasic Word)

问题描述

我正在编写一个脚本来擦洗文档，以格式（USA）来查找缩略词。作为一个处理工具，我需要抓住括号中出现的整个句子。现在我的代码是找到它的缩写：
$ b $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $。 AZ] {2，} \）
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = True
.MatchWildcards = True

将此与Do While .Execute合并，可以梳理文档并找到缩写，然后使用字符串函数我从括号中取出缩写并放在一个表中。有没有一个正则表达式，我可以用它会发现任何一个（美国）类型的首字母缩写词是在？作为一个输入你可以使用这个段落。

非常感谢。

编辑：我找到以下正则表达式来尝试并使其工作：

$ $ $ $ $ $ $ $ c $ .Text =[^。] * \（[AZ] {2， } \）[^。] * \。

但是这给我一个错误，说胡萝卜不能在Find函数中使用。

解决方案

这个正则表达式

  [^ 046] [！^ 046] * \（[AZ] {2,10} \）[！^ 046] * [^ 046] 
   Find 对话框中使用时，p $ p> 
 
 
将会找到一个句子（以句号＃046为界）。注意，这个正则表达式在两端都返回一个完全停止的字符串，例如， 
 
 
 
  
  
。这个字母的首字母缩写（TLA）被使用了。
 
另外请注意，我将首字母缩写的长度限制为10个字符[AZ] {2， 10};根据需要更改上限。 
 
 
 
最后，我观察到，这不会在句子末尾找到缩略词，例如
 
 
我用了一个三个字母的缩写（TLA）。
 
正则表达式的 [！^ 046] * 部分似乎不匹配长度为零的字符串。要捕捉这些情况，您需要使用以下方法进行第二次搜索： 
 
 
  [^ 046] [！^ 046] * \（[AZ] {2,10} \）[^ 046] 
  
  
I'm writing a script that scrubs a document to find acronyms in the format (USA).  As a processing tool I need to grab the entire sentence in which that parenthetical acronym appears.  Right now my code for finding the acronym is:
With oRange.Find
        .Text = "\([A-Z]{2,}\)"
        .Forward = True
        .Wrap = wdFindStop
        .Format = False
        .MatchCase = True
        .MatchWildcards = True
Combining this with a Do While .Execute I can comb the doc and find the acronyms, then using a string function I take the acronym out of the parentheses and put it in a table.  Is there a RegEx that I could use which would find any sentence an (USA) type acronym is in?  As an input you could use this paragraph.

Thank you very much.

edit:  I found the following Regex to try and make it work: 
.Text = "[^.]*\([A-Z]{2,}\)[^.]*\."
But this is giving me an error, saying that the carrot can't be used in the Find function.
解决方案
This regex
[^046][!^046]*\([A-Z]{2,10}\)[!^046]*[^046]
when used in the Find dialog will find a sentence (bounded by full stops ^046). 

Note that this regex returns a string with full stops on both ends, e.g., 

  
. A three-letter acronym (TLA) was used.
Also note that I limited acronym length to 10 chars [A-Z]{2,10}; change the upper limit as needed. 

Finally I observed that this DOES NOT find acronyms at the end of a sentence, e.g. 

  
I used a three-letter acronym (TLA).
The [!^046]* part of the regex does not appear to match a zero length string. To catch those cases you would need to do a second pass search with this:
[^046][!^046]*\([A-Z]{2,10}\)[^046]
Hope that helps

                        
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