FF扩展：带有动态菜单项的弹出框，每个菜单项都有另一个弹出框 [英] FF extension: a popup with dynamic menuitems, with each menu item having another popup

问题描述

我正在构建一个具有弹出式窗口的扩展，每次将鼠标悬停在弹出选项上时，都会通过函数调用来构造元素。我能够做到这一点。现在我需要有一个弹出菜单项（在原来的弹出窗口），这是不是动态的。我有这个代码，但它不起作用：

pre $ var myMenuPopup = document.getElementById（file-popup4）; （var m = 0; m























$ b $

newItem.setAttribute（label，publicdisplayname [m]）;

newItem.setAttribute（id，public+ m）;

var new1 = document.createElement（menuitem）;
new1.setAttribute（label，Home）;
new1.setAttribute（id，publichome+ m）;
newItem.onclick = function（）{
};
newItem.appendChild（new1）;
myMenuPopup.appendChild（newItem）;

但是这不起作用。也就是说，弹出窗口（newitem）没有打开。
有人可以帮我解决这个问题吗？解决方案

你有没有试过onpopupshowing事件（https：// developer.mozilla.org/zh/XUL/menupopup#a-onpopupshowing）？

I am building an extension that has a popup whose elements are constructed by a function call everytime the mouse hovers over the popup option. I am able to achieve this. Now I need to have a popup for each of the menu item (inside the original popup) which is not dynamic though. I have this code, but it does not work:

var myMenuPopup = document.getElementById("file-popup4");

for (var m=0; m<localpubliclist.length; m++)
{

    var newItem = document.createElement("menupopup");

    newItem.setAttribute("label", publicdisplayname[m]);

    newItem.setAttribute("id", "public" + m);

    var new1 = document.createElement("menuitem");
    new1.setAttribute("label","Home");
    new1.setAttribute("id", "publichome" + m);
    newItem.onclick = function(){
    };
    newItem.appendChild(new1);
    myMenuPopup.appendChild(newItem);

but this doesnt work. That is, the popup(newitem) does not open. Can someone please help me out with whats the problem

解决方案

Have you tried the onpopupshowing event (https://developer.mozilla.org/en/XUL/menupopup#a-onpopupshowing)?

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