为什么在Python / Flask中包含sharp(#)符号的非现有URL不是由错误处理程序处理的 [英] Why non existing URL containing the sharp ("#") sign in Python/Flask aren't handled by the errorhandler
问题描述
我正在构建一个Python / Flask(完全是ajax,没有整页重装)web应用程序,当url上的锐利(#)符号变为(本Alman,HashChange事件)
喜欢抓住所有Error-404在我的母版页追加错误页面
考虑以下代码
<
$
from flask import烧瓶,重定向
$ b $ #WebServerGatewayInterface $ b $ class WSGI():
def __init __(self):
self.app = Flask(__ name__)
self.app.debug = True
wsgi = WSGI()
@ wsgi.app.route (/)
def Home():
返回Home
@ wsgi.app.route(/ Contact)
def Contact() :
返回Contact
@ wsgi.app.errorhandler(404)
def PageNotFound(错误):
返回PageNotFound
if __name__ =='__main__':
wsgi.app.run(host ='127.0.0.1',port = 7777)
我想知道为什么当我在sharp(#)符号之后添加一个不存在的URL时,它不会被错误处理程序捕获到?
127.0.0.1:7777
#返回Home
127.0.0.1 :7777 /联系
#返回联系
127.0.0.1:7777/Aasdasdasdasd
#返回PageNotFound
127.0.0.1 :7777 /#/ asdsaasdasdasdas
#它返回Home,这是不正确的,因为这个URL不存在
127.0.0.1:7777/#!/asdsaasdasdasdas
#返回家,不好...
127.0.0.1:7777/#!/Contact
#它返回家,不好...
c>形成资源的片段标识符,并在客户端 。在正常的操作过程中,片段标识符永远不会发送到服务器:
片段标识符的功能与URI的其余部分不同:即,它的处理完全是客户端,没有来自web服务器的参与。
如果一个服务器发送了一个片段标识符一个URL,它必须忽略这部分的URL。这不是路径的一部分,因此,对于所有带有片段的示例URL,Flask只会看到 127.0.0.1:7777 /
。
I'm building a Python/Flask (fully ajax, without full page reloading) web application and I change the content of my master page when the sharp ("#") sign on the url change (Ben Alman, HashChange event)
I would like to catch all Error-404 to append an error page in my master page
Taking the following code in consideration
from flask import Flask, redirect
#WebServerGatewayInterface
class WSGI():
def __init__(self):
self.app = Flask(__name__)
self.app.debug = True
wsgi = WSGI()
@wsgi.app.route("/")
def Home():
return "Home"
@wsgi.app.route("/Contact")
def Contact():
return "Contact"
@wsgi.app.errorhandler(404)
def PageNotFound(error):
return "PageNotFound"
if __name__ == '__main__':
wsgi.app.run(host='127.0.0.1', port=7777)
I would like to understand why when I add a non-exising URL after the sharp ("#") sign, it isn't trapped by the errorhandler ?
E.g.
127.0.0.1:7777
#It returns "Home"
127.0.0.1:7777/Contact
#It returns "Contact"
127.0.0.1:7777/Aasdasdasdasd
#It returns "PageNotFound"
127.0.0.1:7777/#/asdsaasdasdasdas
#It returns "Home", which is not right since this URL doesn't exist
127.0.0.1:7777/#!/asdsaasdasdasdas
#It returns "Home", not ok...
127.0.0.1:7777/#!/Contact
#It returns "Home", not ok...
Everything after the #
forms the fragment identifier of a resource and is handled client side. In the normal course of operation, the fragment identifier is never sent to the server:
The fragment identifier functions differently than the rest of the URI: namely, its processing is exclusively client-side with no participation from the web server
If a server is ever sent a fragment identifier in a URL, it must ignore this part of the URL. It is not part of the path, and thus Flask just sees 127.0.0.1:7777/
for all your sample URLs with a fragment.
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