基于父项的文本字段的字符边界 [英] Character boundaries of text field based on parent

问题描述

我有一个容器内的文本字段。我想知道是否有可能找到每个字符的边界，而不是基于容器而不是文本字段。

这是一个示例屏幕截图：

正常状态会是这样的：
这样我就可以根据文本字段找到每个字符的边界，但是我需要基于容器：

  var rect：Rectangle = new Rectangle（）; 
 for（var i：int = 0; i< textField.length; i ++）{
 rect = textField.getCharBoundaries（i）; 
 
 $ / code> 

有没有人有这方面的经验？ $ b

解决方案

我相信你必须利用Point转换。 c $ c> var rect：Rectangle = new Rectangle（）;
for（var i：int = 0; i< textField.length; i ++）{
rect = textField.getCharBoundaries（i）;

var globalTopLeft：Point = textField.localToGlobal（rect.topLeft）;
var globalBottomRight：Point = textField.localToGlobal（rect.bottomRight）;

var containerTopLeft：Point = container.globalToLocal（globalTopLeft）;
var containerBottomRight：Point = container.globalToLocal（globalBottomRight）;

RECT =新的Rectangle（containerTopLeft.x，containerTopLeft.y，containerBottomRight.x-containerTopLeft.x，containerBottomRight.y-containerTopLeft.y）
}


I have a text field inside a container. I'm wondering is it possible to find the boundaries of each character based on the container and not the text field.

Here is a sample screen shot:

And normal state would be like this: With this I can find the bounds of each character based on text field, But I need it based on the container:

var rect:Rectangle = new Rectangle();
for (var i:int = 0; i < textField.length; i++){
    rect = textField.getCharBoundaries(i);
}

Is there anybody whom has an experience on this?

解决方案

I believe you have to make use of Point conversions.

var rect:Rectangle = new Rectangle();
for (var i:int = 0; i < textField.length; i++){
    rect = textField.getCharBoundaries(i);

    var globalTopLeft:Point = textField.localToGlobal(rect.topLeft);
    var globalBottomRight:Point = textField.localToGlobal(rect.bottomRight);

    var containerTopLeft:Point = container.globalToLocal(globalTopLeft);
    var containerBottomRight:Point = container.globalToLocal(globalBottomRight);

    rect = new Rectangle(containerTopLeft.x,containerTopLeft.y,containerBottomRight.x-containerTopLeft.x,containerBottomRight.y-containerTopLeft.y)
}

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