浮点异常 [英] Floating point exception

问题描述

  #include< stdio.h> 
 #include< math.h> 
 int q; 
 
 int main（）
 {
 srand（time（NULL））; 
 int n = 3; 
 q = ceil（sqrt（n））; 
 printf（％d \ n％d \ n，n，q）; 
 
 if（n == 2）
 printf（％d \ n is prime，n）; 
 else if（n％2 == 0.0 || n <2）
 printf（％d \ n不是素数，n）; 
 else 
 {
 int x; 
 for（x = 0; x  if（n％x == 0）
 {
 printf（％d \ n is not素数，n）; 
 return; 
} 
 else 
 printf（％d \ n is prime，n）; 
 
 
 
 
 
 $ b 
但是当我运行我的代码我得到以下错误：
 
lockquote 
浮点异常
 $ / 
 
 
这个错误意味着什么，我该如何解决它？
当$  x 为0时，你应该把x从2开始。一般说明：
 
 
 
 
尝试更好地设置您的代码的格式。专注于使用一致的风格。例如。你还有一个在if支撑（即使是空格）之后立即开始，另一个在两者之间有换行符。
 
 
除非必要，否则不要使用全局变量。没有理由将 q 设为全局。   在非void（int）函数中不返回值。
 
 
 
I successfully  complied this code:
#include <stdio.h>
#include <math.h>
int q;

int main()
{
    srand( time(NULL) );
    int n=3;
    q=ceil(sqrt(n));
    printf("%d\n %d\n", n,q);

    if(n == 2)
        printf("%d\n is prime", n);
    else if(n % 2 == 0.0 || n < 2)
        printf("%d\n is not prime", n);
    else
    {
        int x;
        for(x = 0; x < q; x++){
            if(n % x == 0)
            {
                printf("%d\n is not prime", n);
                return;
            }
            else
                printf("%d\n is prime", n);
        }
    }
}
But when I run my code I get the following error:

  
Floating point exception
What does this error mean and how can I fix it?
解决方案
It's caused by n % x, when x is 0.  You should have x start at 2 instead. You should not use floating point here at all, since you only need integer operations.


General notes:

Try to format your code better.  Focus on using a consistent style.  E.g. you have one else that starts immediately after a if brace (not even a space), and another with a newline in between.
Don't use globals unless necessary.  There is no reason for q to be global.
Don't return without a value in a non-void (int) function.


                        
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