python：在float数组中找到范围内的值 [英] python: find value within range in float array

问题描述

我有以下的排序python列表，尽管可能会出现多个值：

  [0.0943200769115388，0.17380131294164516,0.4063245853719435，
 0.45796523225774904，0.5040225609708342，0.5229351852840304，
 0.6145136350368882，0.6220712583558284，0.7190096076050408，
 0.8486436998476048，0.8957381707345986，0.9774325873910711，
 0.9832076130275351，0.985386554764682，1.0] 
  

现在，我想知道数组中某个值可能下降的索引：

例如，0.25的值将落在索引 2 中，因为它在0.173和0.40之间。我想我可以通过列表，并在for循环中执行此操作，但是我想知道是否有更好的方法来做到这一点，也许更有效地计算。我创建这个数组一次，但必须执行很多查找。

解决方案

 >> >瓦尔斯= [0.0943200769115388，0.17380131294164516，0.4063245853719435，
 0.45796523225774904，0.5040225609708342，0.5229351852840304，
 0.6145136350368882，0.6220712583558284，0.7190096076050408，
 0.8486436998476048，0.8957381707345986，0.9774325873910711，
 0.9832076130275351，0.985386554764682，1.0] 
 
>>> import bisect 
>>> bisect.bisect（vals，0.25）
 2 
  

I have the following sorted python list, although multiple values can occur:

[0.0943200769115388, 0.17380131294164516, 0.4063245853719435, 
 0.45796523225774904, 0.5040225609708342, 0.5229351852840304, 
 0.6145136350368882, 0.6220712583558284, 0.7190096076050408, 
 0.8486436998476048, 0.8957381707345986, 0.9774325873910711, 
 0.9832076130275351, 0.985386554764682, 1.0]

Now, I want to know the index in the array where a particular value may fall:

For example, a value of 0.25 would fall in index 2 because it is between 0.173 and 0.40. I guess I can go through the list and do this in a for loop but I was wondering if there is some better way to do this which maybe more computationally efficient. I create this array once but have to perform many lookups.

解决方案

>>> vals = [0.0943200769115388, 0.17380131294164516, 0.4063245853719435, 
 0.45796523225774904, 0.5040225609708342, 0.5229351852840304, 
 0.6145136350368882, 0.6220712583558284, 0.7190096076050408, 
 0.8486436998476048, 0.8957381707345986, 0.9774325873910711, 
 0.9832076130275351, 0.985386554764682, 1.0]

>>> import bisect
>>> bisect.bisect(vals, 0.25)
2

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