将float转换为char * [英] Converting float to char*

问题描述

如何在 C 中将 float 值转换为 char * c $ c> language


解决方案

 
 int ret = snprintf（buffer，sizeof buffer，％f，myFloat）; 
 
 if（ret <0）{
 return EXIT_FAILURE; 
 
 if（ret> sizeof buffer）{
 / *结果被截断 - 调整缓冲区的大小并重试。 
 
 
 
 $ b $ p 
 $ b $ p $将会存储 myFloat  code>在 myCharPointer 中。尽管如此，确保字符串足够容纳它。 
 
 
  snprintf 是比<$更好的选项c $ c> sprintf ，因为它保证它永远不会超过你在参数2中提供的缓冲区大小。
 
How can I convert a float value to char* in C language?
解决方案
char buffer[64];
int ret = snprintf(buffer, sizeof buffer, "%f", myFloat);

if (ret < 0) {
    return EXIT_FAILURE;
}
if (ret > sizeof buffer) {
    /* Result was truncated - resize the buffer and retry.
}
That will store the string representation of myFloat in myCharPointer. Make sure that the string is large enough to hold it, though.

snprintf is a better option than sprintf as it guarantees it will never write past the size of the buffer you supply in argument 2.

                        
这篇关于将float转换为char *的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！