根据字体名称和样式（粗体/斜体）获取字体文件名 [英] Get a font filename based on Font Name and Style (Bold/Italic)

问题描述

我需要根据名字得到一个字体文件名（例如Arial.ttf）（在这种情况下是Arial） ），无论是粗体，斜体还是两者。使用这些信息，我需要找到字体文件，所以我可以用它来渲染。

更多的例子：

• Calibri，Bold将解析为calibrib.ttf。


• Calibri，Italic将解析为calibrii.ttf。 b

关于如何在C ++（Win32）中实现这一点的任何想法

首先，据我所知，没有可靠的方法去做。

Windows API处理字体系列和映射，而不是字体文件，在较低的水平处理。还要注意的是，即使你设法得到一个字体的文件名，没有渲染函数（我知道的）会接受它，那么你将如何处理它？<​​/ p>

<这就是说，你可以在注册表键 HKEY_LOCAL_MACHINE \ Software \ Microsoft \ Windows NT \CurrentVersion\Fonts 中以获取文件名来自其逻辑名称的字体。该解决方案的实现可以在这里找到。

This has been driving me crazy all day.

I need to get a font filename (eg. Arial.ttf) based on its name (Arial in this case) and whether it is bold, italic or both. Using those pieces of information, I need to find the font file so I can use it for rendering.

Some more examples:

• Calibri, Bold would resolve to calibrib.ttf.
• Calibri, Italic would resolve to calibrii.ttf.

Any ideas on how I could achieve this in C++ (Win32)

解决方案

First, to my knowledge, there is no reliable way to do that.

The Windows API deals with font families and mappings, not with font files, which are dealt with at a lower level. Also note that even if you manage to get the file name of a font, no rendering function (that I know of) will accept it, so what will you do with it?

That said, you can look in the registry key HKEY_LOCAL_MACHINE\Software\Microsoft\Windows NT\CurrentVersion\Fonts in order to obtain the file name of a font from its logical name. An implementation of that solution can be found here.

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