从一个foreach的php随机顺序 [英] php random order from a foreach

问题描述

  foreach（$ umm as $ data）{
 echo '< img src ='。$ data-> picture。'/>'; 
 echo $ data-> id; 
 
 $ / code $ / pre 
 
现在我想洗牌。我试过了：
 
 $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $' '。$ data-> picture。'/>'; 
 echo $ data-> id; 
 
 $ / code> 

AND



  foreach（$ umm as $ data）{
 $ rand_pic [] = $ data->图片; 
 $ rand_id [] = $ data-> id; 
} 
 $ ran = shuffle（$ rand_id）; 
 foreach（$ ran as $ new）{
 echo'< img src ='。$ new-> picture。'width =100/>'; 
 echo $ new-> id; 
 
 
 
 
 
 
所有这些导致警告：为foreach提供了无效的参数（）在第二个 foreach 中。如何从一个foreach中随机排序？
解决方案
请看  shuffle（） 的文档。它将一个引用引用到一个数组中，并将其置于合适的位置。所以你需要在数组上使用它，然后迭代： 
 
 
  shuffle（$ umm）; 
 $ b foreach（$ umm as $ data）{
 echo'< img src ='。$ data-> picture。'/>'; 
 echo $ data-> id; 
} 
  
 
I have some foreach, this could work well 
foreach ($umm as $data) {
        echo '<img src="'.$data->picture.'" />';
        echo  $data->id;
}
Now I want shuffle the foreach. I tried:
foreach (shuffle($umm) as $data) {
        echo '<img src="'.$data->picture.'" />';
        echo  $data->id;
}
AND
foreach ($umm as $data) {
        $rand_pic[] = $data->picture;
        $rand_id[] = $data->id;
}
$ran = shuffle($rand_id);
foreach($ran as $new){
    echo '<img src="'.$new->picture.'" width="100" />';
    echo $new->id;
}
All these caused Warning: Invalid argument supplied for foreach() in second foreach. How to random order from a foreach?
解决方案
Take a look at the documentation for shuffle(). It takes a reference to an array and shuffles it in place. So you need to use it on the array, then iterate:
shuffle($umm);

foreach ($umm as $data) {
        echo '<img src="'.$data->picture.'" />';
        echo  $data->id;
}


                        
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