我将如何迭代一个文件列表,并将它们绘制成一个图上的子图? [英] How would I iterate over a list of files and plot them as subplots on a single figure?
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问题描述
我几乎在最后一步(用斧头),但需要指导如何完成它。
这里是我的代码:
pre $ import $ matplotlib.pyplot as plt
import parse_gctoo
import glob
f,ax1 = plt.subplots()
def histo_plotter(file,plot_title,ax):
#以字符串形式读入文件
GCT_object = parse_gctoo.parse (文件)
#为范围(9)中的c:
#打印类型(GCT_object.data_df.iloc [0] [c])
#计算data_df中行的中位数$ b $格式(单元格)
如果plot_title ==ZSPCQNORM:b#gene_medians = GCT_object.data_df.quantile(q = 0.5,axis = 1)
#plot_title =
gene_means = GCT_object.data_df.mean(axis = 1)
#制作手段的直方图
ax.hist(gene_means)
plt.title(MeanGeneExpressionZSPCQNORM)
plt.xlabel(MedianGeneExpression)
plt.ylabel(Count)
elif plot_title ==QNORM:
gene_medians = GCT_object.data_df.median(axis = 1)
#制作媒体直方图
ax.hist(gene_medians)
plt.title(MedianGeneExpressionQNORM)
plt.xlabel(MedianGeneExpression)
plt.ylabel(Count)
plt.show()
f.savefig(hist_example1.png)
#plt.ylim(-1,1)
#plt.xlim(-1,1)
#histo_plotter(/ Users / eibelman / Desktop / ZSCOREDATA- CXA061_SKL_48H_X1_B29_ZSPCQNORM_n372x978.gct.txt,ZSPCQNORM,ax1)
#histo_plotter (/Users/eibelman/Desktop/NewLJP005_A375_24H_X2_B19_QNORM_n373x978.gct.txt,QNORM,ax1)
#########
#创建x2 LJP005单元格文件列表
z_list = glob.glob(/ Volumes / cmap_obelix / pod / custom / LJP / roast / LJP005_ [A375,A549,BT20,HA1E,HC515, HEPG2,HS578T,HT29] * X2 * / zs / * ZSPCQNORM * .gct)
q_list = glob.glob(/ Volumes / cmap_obelix / pod / custom / LJP / roast / LJP005_ [A375,A549,BT20 ,HA1E,HC515,HEPG2,HS578T,HT29] * _ X2 _ * / * _ QNORM _ *。gct)
#for循环允许绘制多个文件(q_list):
f,axarray = plt.subplots(2,4)
),1,n + 1)
axarray = histo_plotter(n,QNORM,ax1)
#axarray [n] .plot()
plt.show()
#f,axarray = plt.subplots(2,4)
#for n,single_z枚举(z_list):
##ax = plt.subplot(len(z_list),1 ,n + 1)
#histo_plotter(single_z,ZSPCQNORM,ax1)'
import matplotlib.pyplot as plt
$> b $ b plt.figure()
for n,枚举中的single_q(q_list):
ax = plt.subplot(len(q_list),1,n + 1)$ b $ (b)GCT_object = parse_gctoo.parse(single_q)
gene_medians = GCT_object.data_df.median(axis = 1)
plt.hist(gene_medians)
#调整标题,标签等
plt.show()
解释:
-
enume (
n
);同时返回它们的下标(n)。
- 函数
子图(size,column,row)
需要这些参数:size
是图中子图的总数,而row
和列
确定当前图的位置。n + 1
有必要将图表沿着图形网格放置在正确的位置上;
- 我编辑了其余的代码您自己的数据
I'm trying to plot files onto 8 subplots for 2 figures. I am using a for loop and enumerate operator, along with axarray to do this. I am almost there with the last step (with axarray) but need guidance as to how to finish it. Here's my code:
'import matplotlib.pyplot as plt
import parse_gctoo
import glob
f, ax1 = plt.subplots()
def histo_plotter(file, plot_title, ax):
# read in file as string
GCT_object = parse_gctoo.parse(file)
# for c in range(9):
# print type(GCT_object.data_df.iloc[0][c])
# computing median of rows in data_df
# gene_medians = GCT_object.data_df.quantile(q=0.5,axis=1)
# plot_title = "Gene expression levels for {}".format(cell)
if plot_title == "ZSPCQNORM":
gene_means = GCT_object.data_df.mean(axis=1)
#making histogram of means
ax.hist(gene_means)
plt.title("MeanGeneExpressionZSPCQNORM")
plt.xlabel("MedianGeneExpression")
plt.ylabel("Count")
elif plot_title == "QNORM":
gene_medians = GCT_object.data_df.median(axis=1)
#making histogram of medians
ax.hist(gene_medians)
plt.title("MedianGeneExpressionQNORM")
plt.xlabel("MedianGeneExpression")
plt.ylabel("Count")
plt.show()
f.savefig("hist_example1.png")
# plt.ylim(-1, 1)
# plt.xlim(-1,1)
# histo_plotter("/Users/eibelman/Desktop/ZSCOREDATA- CXA061_SKL_48H_X1_B29_ZSPCQNORM_n372x978.gct.txt", "ZSPCQNORM", ax1)
# histo_plotter("/Users/eibelman/Desktop/NewLJP005_A375_24H_X2_B19_QNORM_n373x978.gct.txt", "QNORM", ax1)
#########
# Create list of x2 LJP005 cell line files
z_list = glob.glob("/Volumes/cmap_obelix/pod/custom/LJP/roast/LJP005_[A375, A549, BT20, HA1E, HC515, HEPG2, HS578T, HT29]*X2*/zs/*ZSPCQNORM*.gct")
q_list = glob.glob("/Volumes/cmap_obelix/pod/custom/LJP/roast/LJP005_[A375, A549, BT20, HA1E, HC515, HEPG2, HS578T, HT29]*_X2_*/*_QNORM_*.gct")
# for loop which allows plotting multiple files in a single figure
f, axarray = plt.subplots(2, 4)
for n, single_q in enumerate(q_list):
# axarray = plt.subplot(len(q_list), 1, n+1)
axarray = histo_plotter(n, "QNORM", ax1)
# axarray[n].plot()
plt.show()
# f, axarray = plt.subplots(2, 4)
# for n, single_z in enumerate(z_list):
# # ax = plt.subplot(len(z_list), 1, n+1)
# histo_plotter(single_z, "ZSPCQNORM", ax1)'
解决方案
You can try this:
import matplotlib.pyplot as plt
plt.figure()
for n, single_q in enumerate(q_list):
ax = plt.subplot(len(q_list), 1, n+1)
GCT_object = parse_gctoo.parse(single_q)
gene_medians = GCT_object.data_df.median(axis=1)
plt.hist(gene_medians)
# tweak title, labels, etc.
plt.show()
Explaining:
enumerate
iterates over the items (s
) while also returning their indices (n
);- the function
subplot(size, column, row)
requires these parameters:size
is the total amount of subplots in the figure, androw
andcolumn
determine the position for the current plot.n+1
is necessary to put the plot in the correct position along the plot grid; - I edited the rest of the code with your own data
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