for循环没有在java中的大括号 [英] for loop without braces in java

问题描述

我想知道为什么这两个代码给出了不同的结果;

pre> for（i = 1，j = 0; i< ; 10; i ++）{
j + = i;
System.out.println（i）;







这个数字给出了1个包含的数字和10个被排除的数字。对于（i = 1，j = 0; i <10; i ++）
j + = i，



  
 System.out.println（i）; 
  

然而这个给出了10.我无法得到这个逻辑;



  for（）
 do_something; 
 do_something_else; 
  




解决方案

这是因为迭代的默认范围是只有跟在它后面的行，在你的情况下，相当于 - （$ = $，$，$，$，$，$，$，$，$，$，$） ; i ++）{
j + = i;
}
System.out.println（i）;


因此整个循环都是迭代的，从那以后i == 10的值，就是你的在第二种情况下输出。

---

在第一种情况下，非常明显的是每次迭代打印值1至9（小于10）：对于（i = 1，j = 0; i <10; i ++）{b
$ b

  
j + = i; 
 System.out.println（i）; 
} 
  

I wonder why this two following codes give different results;

for(i = 1, j = 0; i < 10; i++) {
    j += i;
    System.out.println(i);
}

This one gives the numbers between 1 included and 10 excluded.

for(i = 1, j = 0; i < 10; i++)
    j += i;
System.out.println(i);

However this one gives 10. I could not get the logic of this;

for()
do_something;
do_something_else;

解决方案

That is because the default scope of an iteration is the only following line after it, in your case something equivalent to -

for(i=1, j=0;i<10;i++) {
    j += i;
}
System.out.println(i);

Hence the entire loop is iterated and since after that the value of i==10, that is your output in the second case.

---

In the first case, it's pretty obvious that the value is printed with each iteration and hence 1 to 9(less than 10) :

for(i=1, j=0;i<10;i++){
    j += i;
    System.out.println(i);
}

这篇关于for循环没有在java中的大括号的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！