Java Regex在大括号之间获取数据 [英] Java Regex to get Data between curly brackets

问题描述

我正在寻找一个正则表达式来匹配花括号之间的文本。

I am looking for a regular expression to match the text between curly brackets.

{one}{two}{three}

我希望每个人都是单独的组，因为一个 两个 三个分开。

I want each of these as separate groups, as one two three separately.

我试过 Pattern.compile（\\ {。 *？\\}）; 仅删除第一个和最后一个花括号

I tried Pattern.compile("\\{.*?\\}"); which removes only first and last curly brackets

谢谢。

推荐答案

您需要使用捕获组（）围绕您想捕获的内容。

You need to use a capturing group ( ) around what you want to capture.

仅匹配并捕捉大括号之间的内容。

To just match and capture what is between your curly brackets.

String s  = "{one}{two}{three}";
Pattern p = Pattern.compile("\\{([^}]*)\\}");
Matcher m = p.matcher(s);
while (m.find()) {
  System.out.println(m.group(1));
}

输出

one
two
three

如果你想要三个特定的匹配组...

If you want three specific match groups...

String s  = "{one}{two}{three}";
Pattern p = Pattern.compile("\\{([^}]*)\\}\\{([^}]*)\\}\\{([^}]*)\\}");
Matcher m = p.matcher(s);
while (m.find()) {
  System.out.println(m.group(1) + ", " + m.group(2) + ", " + m.group(3));
}

输出

one, two, three

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