Python 删除大括号之间的空格 [英] Python remove spaces in between braces

问题描述

我正在使用 re 但我没有任何运气.我想知道如何删除大括号之间的空格.例如

我有这个字符串

 我想去[超级商场](地点)

你看到[超级商场]"的空间了吗?

什么可以把这个字符串变成

 我要去【超级商场】(地点)

如果我能在这方面得到任何帮助，我将不胜感激.

解决方案

我假设大括号是平衡的，不能嵌套.

<预><代码>>>>进口重新>>>s = '我想去[超级商场](地方)[真正的]'>>>re.sub('\[\s*(.*?)\s*\]', r'[\1]', s)'我想去[超级商场](地方)[真的]'

<块引用>

它不适用于多个.就像我想去[超级商场](地方)和[奶酪商场](地方)

我认为是的.

<预><代码>>>>s = '我想去[超级商场](地点)和[奶酪商场](地点)'>>>re.sub('\[\s*(.*?)\s*\]', r'[\1]', s)'我想去[超级商场](地方)和[奶酪商场](地方)'

I am using re but I am not having any luck. I want to know how to remove spaces in between braces. For example

I have this string

     i want to go to the[ super mall ](place)

You see the the space in "[ super mall]"?

What can turn this string into

      i want to go to the [super mall](place)

I would appreciate any help I can get on this thanks.

解决方案

I'm assuming braces are balanced and cannot be nested.

>>> import re
>>> s = 'i want to go to the[super mall](place) [ for real    ]'
>>> re.sub('\[\s*(.*?)\s*\]', r'[\1]', s)
'i want to go to the[super mall](place) [for real]'

It doesn't work for multiple ones. like i want to go to the [ super mall ](place) and [ cheese mall ](place)

I think it does.

>>> s = 'i want to go to the [ super mall ](place) and [ cheese mall ](place)'
>>> re.sub('\[\s*(.*?)\s*\]', r'[\1]', s)
'i want to go to the [super mall](place) and [cheese mall](place)'

这篇关于Python 删除大括号之间的空格的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！