如何遍历基本算术符号 [英] how to loop over the elementary arithmetic symbols
本文介绍了如何遍历基本算术符号的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
I want to check if 7 digits can get to 100 when putting elementary arithmetic symbols between them.
def is_hundred(n1,n2,n3,n4,n5,n6,n7):
p = [+,-,*,/]
for p1 in p:
for p2 in p:
for p3 in p:
for p4 in p:
for p5 in p:
for p6 in p:
if n1 p1 n2 p2 n3 p3 n4 p4 n5 p5 n6 p6 n7 == 100:
return "success"
如何用算术替换变量符号在列表中?
how can i replace the variables with the arithmetic symbols that are in the list?
推荐答案
这是一个搜索一对运算符的示例代码。 iadd
中的 i
表示inplace add
运算符。你可以简单地切换到 add
。 product
会创建运算符的重复排列。
Here is a sample code which search a pair of operators. the i
in iadd
means inplace add
operator. You can simply switch to add
. product
creates duplicate permutation of operators.
from operator import iadd, isub, imul, itruediv
from itertools import product
operators = (iadd, isub, imul, itruediv)
def is_hundred(values):
n_operators = len(values) - 1
for ops in product(operators, repeat=n_operators):
value = values[0]
for op, v in zip(ops, values[1:]):
value = op(value, v)
if value == 100:
print(list(ops))
return True
else:
return False
print(is_hundred([99,1,1,1,1,1]))
print(is_hundred([1,1,1,1]))
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