在java中使用三种方法和一个for循环来寻找平均值 [英] Finding average using three methods and a for loop in java

问题描述

package averagewithmethods;

import java.util.Scanner;

  public class AverageWithMethods {
 
 public static void main（String [] args）{
 String userInput =; 
 double avgVal = 0; 
 // calculateAvg（userInput）; 
 // getUserInput（）; 
 printResults（userInput，avgVal）; 
 
 
 public static String getUserInput（）{
 String userInput; 
扫描仪scnr =新扫描仪（System.in）; 
 System.out.print（请在一行中输入最多十个数字：）; 
 userInput = scnr.nextLine（）; 
返回userInput; 
 
 
 public static double calculateAvg（String userInput）{
 double avgVal = 0; 
 double totSum = 0; 
 int i; 
 String newUserInput [] = getUserInput（）。split（）; 
 double [] userInputArray = new double [newUserInput.length]; 
 
 for（i = 0; i< newUserInput.length; ++ i）{
 String userInputString = newUserInput [i]; 
 userInputArray [i] = Double.parseDouble（userInputString）; 
 totSum + = userInputArray [i]; 
 avgVal = totSum / newUserInput.length; 
} 
 return avgVal; 
 
 $ b $ public static void printResults（String userInput，double avgVal）{
 System.out.println（数字的平均值+ getUserInput（）+is + calculateAvg（userInput））; 
} 
} 
  

这是我的输出。

 请在一行中输入最多10个数字：10 20 30 
请在一行中输入最多十个数字：10 20 30 
数字10 20 30的平均值是20.0 
 BUILD SUCCESSFUL（总计时间：6秒）
  

我只需要知道为什么提示符（请输入最多十个数字在一行中：）打印两次

getUserInput（）方法两次：一次在 printResults（）方法，一次在 calculateAvg（）中。

您可能想要更改：

  String newUserInput [] = getUserInput（）。split（）; 
  

到

  String newUserInput [] = userInput.split（）; 
  

package averagewithmethods;

import java.util.Scanner;

public class AverageWithMethods {

    public static void main(String[] args) {
        String userInput = "";
        double avgVal = 0;
        //calculateAvg(userInput);
        //getUserInput();
        printResults(userInput, avgVal);
    }

    public static String getUserInput() {
        String userInput;
        Scanner scnr = new Scanner(System.in);
        System.out.print("Please enter up to ten numbers in one line: ");
        userInput = scnr.nextLine();
        return userInput;
    }

    public static double calculateAvg(String userInput) {
        double avgVal = 0;
        double totSum = 0;
        int i;
        String newUserInput[] = getUserInput().split(" ");
        double[] userInputArray = new double[newUserInput.length];

        for (i = 0; i < newUserInput.length; ++i) {
            String userInputString = newUserInput[i];
            userInputArray[i] = Double.parseDouble(userInputString);
            totSum +=userInputArray[i];
            avgVal = totSum/newUserInput.length;
        }
        return avgVal;
    }

    public static void printResults(String userInput, double avgVal) {
        System.out.println("The average of the numbers " + getUserInput() + " is " + calculateAvg(userInput));
    }
}

This is my output.

Please enter up to ten numbers in one line: 10 20 30
Please enter up to ten numbers in one line: 10 20 30
The average of the numbers 10 20 30 is 20.0
BUILD SUCCESSFUL (total time: 6 seconds)

The only thing I need to know is why does the prompt ("Please enter up to ten numbers in one line: ") print twice

解决方案

You're calling the getUserInput() method twice: once in the printResults() method and once in the calculateAvg().

You probably want to make the following change:

String newUserInput[] = getUserInput().split(" ");

to

String newUserInput[] = userInput.split(" ");

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