如何在字符串中找到元音，并在屏幕上打印出元音最多的单词？ [英] How do I find vowels in a string, and print the word with the most vowels on the screen?

问题描述

我需要在用户输入的字符串中找到所有的元音，然后在屏幕上打印出最多的元音。

程序使用用户输入。

用户在小写字母串中输入。

eg

我喜欢Java编程

它应该读出：

编程

我尝试将字符串拆分成不同的单词，并且工作。

我只是不知道如何应用for循环来搜索不同的单词。
我需要在方法中工作，所以这是我用来在字符串中查找元音的方法：

  public void findvowel（）{
 for（int index = 0; index< word.length（）; index ++）{
 char vowel = word.charAt（index）; （元音=='a'）|| 
（vowel =='e'）|| 
（元音=='i'）|| 
（元音=='o'）|| 
（vowel =='u'））{
 System.out.println（vowel）; 
 
 
 
 
 
 
但是我知道这不是'工作。 
您可以帮助我吗？
 
解决方案
 
  public class MaxVowels {
 public static void main（String [] args）{
 String sentence =This is a loooooooooong sentence; 
 int maxVowelCount = 0; 
 String wordsWithMostVowels = null; 
 String [] words = sentence.split（）; 
 
 for（String word：words）{
 int vowelCount = 0; 
 word = word.toLowerCase（）; 
 for（int i = 0; i< word.length（）; i ++）{
 char x = word.charAt（i）; 
 if（x =='a'|| x =='e'|| x =='i'|| 
x =='o'|| x =='u'）{
 vowelCount ++; 
 
 
 if（vowelCount> maxVowelCount）{
 maxVowelCount = vowelCount; 
 wordsWithMostVowels =单词; 
 
 $ b System.out.println（大多数元音字是：+ wordsWithMostVowels）; 
 
 
 
 
 
 
 
代码相当简单，不需要解释=） 
 
这段代码忽略了两个单词的元音数量相同的情况。在这种情况下，第一个单词将被用作大多数元音字。
 
I need to find all vowels in a user inputted string, and then print the word with the most vowels on the screen.

The program uses user input.

The user types in a string of words in lowercase.

e.g. 

  
"I like java programming"  
and it should read out:

  
programming
I tried splitting the string into different words, and that works.

I only don't know how to apply a "for" loop to search in the different words.
I need to work in methods, so this is the method I used to find vowels in the string:
public void findvowel(){
    for(int index = 0;index < word.length();index++){
    char vowel = word.charAt(index);
    if( (vowel == 'a')||
        (vowel == 'e')||
        (vowel == 'i')||
        (vowel == 'o')||
        (vowel == 'u')){
            System.out.println(vowel);
            }
        }
    }
But I know this doesn't work. 
Can you people help me?
解决方案
public class MaxVowels {
    public static void main(String[] args) {
        String sentence = "This is a loooooooooong sentence";
        int maxVowelCount = 0;
        String wordsWithMostVowels = null;
        String[] words = sentence.split(" ");

        for(String word : words){
            int vowelCount = 0;
            word = word.toLowerCase();
            for(int i = 0; i < word.length() ; i++){
                char x = word.charAt(i);
                if(x == 'a' || x == 'e' || x == 'i' ||
                   x == 'o' || x == 'u'){
                    vowelCount++;
                }
            }
            if(vowelCount > maxVowelCount){
                maxVowelCount = vowelCount;
                wordsWithMostVowels = word;
            }
        }
        System.out.println("Word with most vowels is: " + wordsWithMostVowels);
    }
}  
The code is fairly straightforward and needs no explanation =)

The code ignores the case where two words have the same number of vowels. In this case, the first word will be used as the word with most vowels.

                        
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