如何打印“\ n”而不是换行符？ [英] How to print '\n' instead of a newline?

问题描述

我正在写一个程序，使用它的输入打印一个十六进制转储。然而，我遇到了新行，标签等传入和销毁我的输出格式的问题。

我怎样才能使用printf（或猜测）打印\ n，而不是打印一个实际的换行符？我只需要为此做一些手动解析？

编辑：我正在动态接收我的数据，这不仅仅是我关于，而是所有的符号。例如，这是我的printf语句：

  printf（％c，theChar）; 
  

当一个换行符作为theChar传入时，如何使这个print \\\
成为可能当Char是一个有效的可打印字符时打印普通文本？

解决方案

打印\\ - \\ 产生\，然后n被识别为普通符号。有关详情，请参阅此处。

I am writing a program that uses prints a hex dump of its input. However, I'm running into problems when newlines, tabs, etc are passed in and destroying my output formatting.

How can I use printf (or cout I guess) to print '\n' instead of printing an actual newline? Do I just need to do some manual parsing for this?

EDIT: I'm receiving my data dynamically, it's not just the \n that I'm corned about, but rather all symbols. For example, this is my printf statement:

printf("%c", theChar);

How can I make this print \n when a newline is passed in as theChar but still make it print normal text when theChar is a valid printable character?

解决方案

Print "\\n" – "\\" produces "\" and then "n" is recognized as an ordinary symbol. For more information see here.

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