如何在发送时不用打开新页面而使用php / ajax发送表单 [英] How to send a form with php / ajax without opening a new page when send
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问题描述
我有一个小表单,如果表单发送或出错,我试图返回一个ajax错误。
在connection.php中我有一个提交表单的脚本
if($ _ POST ['postForm'] =='newsletter'){
$ newsletterSubscriber = new NewsletterSubscriber();
$ newsletterSubscriber-> set('CMS_newsletters_id',2);
$ newsletterSubscriber-> set('created',date('Y-m-d H:i:s'));
$ newsletterSubscriber-> set('firstName',$ _POST ['voornaam']);
$ newsletterSubscriber-> set('lastName',$ _POST ['achternaam']);
$ newsletterSubscriber-> set('companyName',$ _POST ['beddrijfsnaam']);
$ newsletterSubscriber-> set('emailAddress',$ _POST ['email']);
$ newsletterSubscriber-> set('subscribed',1);
$ saved = $ newsletterSubscriber-> save();
$ response = array('error_code'=> 0,
'message'=>'订阅者添加'
);
echo json_encode($ response);
出口;
}
在我的scripts.js中我有我的ajax:
$。ajax({
type:POST,
url:connection.php,
data :{param1:'aaa'},
dataType:JSON
})
.done(function(data){
if(data.error_code == 0){
alert(data.message);
}
}
});
我收到的错误是:
SyntaxError:意外标记'}'。预期')'结束参数列表。
有人可以看到我做错了吗?
$。ajax({
类型:POST,
url:connection.php,
data:{param1:'aaa'},
dataType:JSON
})
.done(函数(数据){
if(data.error_code == 0){
alert(data.message);
}
//你有一个extra} here。
});
I have a little form and I'm trying to return a ajax error if the form is send or when something went wrong.
in connection.php I have a little script that submits the form
if($_POST['postForm'] == 'newsletter'){
$newsletterSubscriber = new NewsletterSubscriber();
$newsletterSubscriber->set('CMS_newsletters_id', 2);
$newsletterSubscriber->set('created', date('Y-m-d H:i:s'));
$newsletterSubscriber->set('firstName', $_POST['voornaam']);
$newsletterSubscriber->set('lastName', $_POST['achternaam']);
$newsletterSubscriber->set('companyName', $_POST['beddrijfsnaam']);
$newsletterSubscriber->set('emailAddress', $_POST['email']);
$newsletterSubscriber->set('subscribed', 1);
$saved = $newsletterSubscriber->save();
$response = array('error_code'=>0,
'message'=>'subscriber added'
);
echo json_encode($response);
exit;
}
in my scripts.js I have my ajax:
$.ajax({
type: "POST",
url: "connection.php",
data: {param1: 'aaa'},
dataType: JSON
})
.done( function(data){
if(data.error_code == 0) {
alert(data.message);
}
}
});
The error that I receive is:
SyntaxError: Unexpected token '}'. Expected ')' to end a argument list.
Can somebody see what I'm doing wrong?
解决方案
Your JavaScript code has an error:
$.ajax({
type: "POST",
url: "connection.php",
data: {param1: 'aaa'},
dataType: JSON
})
.done( function(data){
if(data.error_code == 0) {
alert(data.message);
}
//You had an extra } here.
});
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