如何使用jQuery.ajax()在PHP脚本中访问从HTML页面传递的表单数据的各个值? [英] How to access individual values of form data, passed from an HTML page with jQuery.ajax(), inside a PHP script?
问题描述
我将表单数据传递给PHP脚本以通过JS进行处理( jQuery.ajax()
)。
问题是 - 我找不到一种方法来访问PHP内的单个窗体控件值(例如 $ _ POST ['zipcode']
)。
相反,我只能使用 $ _ POST ['form']
访问数据,这是一个完整的表示形式(例如 string(89)color = red& color = blue& zipcode = 12345 ...
)。
如何通过JS从HTML表单传递PHP脚本中的表单数据的单个值?
index.php(form)
< form id =myform>
< select name =colorid =color>
< option value =Red>红色< / option>
< option value =Green>绿色< / option>
< option value =Blue>蓝色< / option>
< / select>
< input type =textid =zipcodename =zipcode/>
< input type =submitid =submitname =submitvalue =Submit/>
< / form>
index.php(JS) type:'POST',
dataType:'html',
url:'PHPscript.php',
data:{form:$('#myform ').serialize()}
})。done(function(data){
var myJSONresult = data;
alert(myJSONresult);
});
});
PHPscript
<?php
if(isset($ _ POST [form])){
$ form = $ _POST [form];
$ myzipcode = $ _POST ['zipcode']; //不行;将为空或空
echo json_encode($ form);
}
?>
编辑: 邮编字段:
$(#zipcode)。focus(function(){
if(this.value ==zipcode ){
$(this).val();
}
})。blur(function(){
if(this.value ==) {
$(this).val(zipcode);
}
});
您需要在表单数据上使用serializeArray而不是序列化。
$ b
data:$('#myform')。serializeArray()
code>
HTML
< input type =hiddenname =actionvalue =submit/>
PHP
if(isset($ _ POST [action]))
{
// code
}
I'm passing form data to a PHP script for processing via JS(jQuery.ajax()
).
Problem is - I can't figure out a way to access individual form control values inside PHP( e.g. $_POST['zipcode']
).
Instead I can only access the data with $_POST['form']
, which is an entire form represented as one long string( e.g. string(89)"color=red&color=blue&zipcode=12345..."
).
How can I access individual values of form data inside PHP script passed from a HTML form via JS?
index.php(form)
<form id="myform">
<select name="color" id="color">
<option value="Red">Red</option>
<option value="Green">Green</option>
<option value="Blue">Blue</option>
</select>
<input type="text" id="zipcode" name="zipcode" />
<input type="submit" id="submit" name="submit" value="Submit" />
</form>
index.php(JS)
$('#myform').on('submit', function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
dataType: 'html',
url : 'PHPscript.php',
data: {form : $('#myform').serialize()}
}).done(function(data) {
var myJSONresult = data;
alert(myJSONresult);
});
});
PHPscript
<?php
if(isset($_POST["form"])){
$form = $_POST["form"];
$myzipcode = $_POST['zipcode']; // won't work; will be null or empty
echo json_encode($form);
}
?>
EDIT: The zipcode field:
$("#zipcode").focus(function(){
if(this.value == "zipcode"){
$(this).val("");
}
}).blur(function(){
if(this.value == ""){
$(this).val("zipcode");
}
});
You need to use serializeArray() on the form data instead of serialize. That will submit as an array.
data: $('#myform').serializeArray()
HTML
<input type="hidden" name="action" value="submit" />
PHP
if(isset($_POST["action"]))
{
//code
}
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