如何使用PHP将文本发布到HTML [英] How to post text to HTML with PHP
问题描述
好的，我在这里之后是检查复选框是否被选中，如果有的话，我想将文本添加到< ul> 类的名称，比方说，确认，所以< ul class =confirmed> ，
如果它没有被选中，那么我会将文本添加到一个名为< ul> 的类中未经证实。现在我有了检查复选框是否已被确认的php代码（见下面），但我不知道在这些陈述中要添加什么。这是我需要帮助/指导的地方。
PHP IF代码（勾选复选框）：
<$ p如果（isset（$ _POST [checkbox1]））{
//写入< ul>< code><？php
if班级确认
} else {
//写入< ul> class unconfirmed
}
？>
这是我的HTML代码：
<身体GT;
< div id =content>
< div class =jumbotron>
< h1>周三是否有橄榄球？< / h1>
< h2>是。< / h2>
< / div>
< div class =alert alert-inforole =alert>已确认的玩家< / div>
< ul class =list-group>
< li class =list-group-item>
<！ - 这是如果复选框被选中，php代码的结果将到哪里 - >
Lorem Ipsor
< / li>
< / ul>
< div class =alert alert-dangerrole =alert>未经确认的玩家< / div>
< li class =list-group-item>
<！ - 如果复选框没有被选中，这是php代码的结果。
Lorem Ipsor
< / li>
< / div>
<！ - form - >
< form action =check.phpmethod =POST>
< input type =checkboxname =checkbox1>
< input type =submit>< / input>
< / form>
< / body>
抱歉，如果我似乎让你感到困惑，正如我所说的，我不太好。任何帮助/指导都会很棒！
好吧，当您勾选一个复选框时，它应该通过$ _POST返回一个值提交时为1或0。您可以修改您的模板，如下所示：
<？php
if（$ _POST ['checkbox1']） {
$ class ='confirmed';
}
else {
$ class ='unconfirmed';
}
？>
< body>
< div id =content>
< div class =jumbotron>
< h1>周三是否有橄榄球？< / h1>
< h2>是。< / h2>
< / div>
< div class =alert alert-inforole =alert>已确认的玩家< / div>
< ul class =list-group<？php echo $ class;？>>
< li class =list-group-item>
Lorem Ipsor
< / li>
< / ul>
< div class =alert alert-dangerrole =alert>未经确认的玩家< / div>
< / div>
<！ - form - >
< form action =check.phpmethod =POST>
< input type =checkboxname =checkbox1/>
< input type =submit/>
< / form>
< / body>
为了确保您始终可以var_dump $ _POST来查看其中的内容并修改您的如果声明更准确，则应返回1或0 iirc。
Okay so what I am after for here is to check if a checkbox has been ticked, if it has, then I would like to add the text into a <ul> class named, let's say, "confirmed", so <ul class="confirmed">,
If it hasn't been checked, then I would add the text to a <ul> class named "unconfirmed". Now I have the php code that checks if the checkbox has been confirmed (seen below), but I don't know what to add inside the statements. This is where I need help/guidance.
PHP IF code (Check if checkbox is ticked):
<?php
if (isset($_POST["checkbox1"])){
//write to <ul> class confirmed
} else {
//write to <ul> class unconfirmed
}
?>
Here's my HTML Code:
<body>
<div id="content">
<div class="jumbotron">
<h1>Is there football on Wednesday?</h1>
<h2>Yes.</h2>
</div>
<div class="alert alert-info" role="alert">Confirmed Players</div>
<ul class="list-group">
<li class="list-group-item">
<!--this is where to result of the php code would go if the checkbox is checked-->
Lorem Ipsor
</li>
</ul>
<div class="alert alert-danger" role="alert">Unconfirmed Players</div>
<li class="list-group-item">
<!--this is where to result of the php code would go if the checkbox is not checked-->
Lorem Ipsor
</li>
</div>
<!--form-->
<form action="check.php" method="POST">
<input type="checkbox" name="checkbox1">
<input type="submit"></input>
</form>
</body>
Sorry if I seem to be confusing you, as I said, I'm not too well. Any help/guidance would be great!
Alright so when you tick a checkbox it should return a value through the $_POST which is 1 or 0 on submit. You may modify your template like this:
<?php
if ($_POST['checkbox1']) {
$class = 'confirmed';
}
else {
$class = 'unconfirmed';
}
?>
<body>
<div id="content">
<div class="jumbotron">
<h1>Is there football on Wednesday?</h1>
<h2>Yes.</h2>
</div>
<div class="alert alert-info" role="alert">Confirmed Players</div>
<ul class="list-group <?php echo $class; ?>">
<li class="list-group-item">
Lorem Ipsor
</li>
</ul>
<div class="alert alert-danger" role="alert">Unconfirmed Players</div>
</div>
<!--form-->
<form action="check.php" method="POST">
<input type="checkbox" name="checkbox1" />
<input type="submit" />
</form>
</body>
To be sure you can always var_dump the $_POST to see what is coming through in it and modify your if statement to be more accurate, it should return 1 or 0 iirc.
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