如何启动一个Intent传递一些参数呢？ [英] How to start an Intent by passing some parameters to it?

问题描述

我想通过我的ListActivity的构造函数一些变量

I would like to pass some variables in the constructor of my ListActivity

我通过这个code开始的活动：

I start activity via this code:

startActivity(new Intent (this, viewContacts.class));

我想用类似code，但两个字符串传递给构造函数。怎么可能？

I would like to use similar code, but to pass two strings to the constructor. How is possible?

推荐答案

为了通过创建新的目标参数，把参数映射：

In order to pass the parameters you create new intent and put a parameter map:

Intent myIntent = new Intent(this, NewActivityClassName.class);
myIntent.putExtra("firstKeyName","FirstKeyValue");
myIntent.putExtra("secondKeyName","SecondKeyValue");
startActivity(myIntent);

为了得到开始活动里面的参数值，你必须调用获取【类型】超（）在同一个目的：

In order to get the parameters values inside the started activity, you must call the get[type]Extra() on the same intent:

// getIntent() is a method from the started activity
Intent myIntent = getIntent(); // gets the previously created intent
String firstKeyName = myIntent.getStringExtra("firstKeyName"); // will return "FirstKeyValue"
String secondKeyName= myIntent.getStringExtra("secondKeyName"); // will return "SecondKeyValue"

如果你的参数是整数，你会使用 getIntExtra（）代替等。 现在你可以使用你的参数，就像你通常会。

If your parameters are ints you would use getIntExtra() instead etc. Now you can use your parameters like you normally would.

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