错误：期望（1）处的表达式中有右括号， [英] Error: Expected a right parenthesis in expression at (1)

问题描述

它显示期望在表达式中有一个右括号，虽然我已经多次检查过它了。

  do i = 0，m- （i（i，j）/ dx）*（（0.02651995 * pho（i + 3， j）条） - （0.18941314 * PHO第（i + 2，j）的）+（0.79926643 * PHO第（i + 1，j）的） - （0.79926643 * PHO第（i-1，j）的）+（0.18941314 * PHO（异2，J）） - （0.02651995 * PHO（I-3，J））））+（（X（I，J）/ DY）*（（0.02651995 * PHO第（i + 3，j）的） - （0.18941314 * PHO第（i + 2，j）的）+（0.79926643 * PHO第（i + 1，j）的） - （0.79926643 * PHO第（i-1，j）的）+（0.18941314 * PHO（I-2，J）） - （ 0.02651995 * pho（i-3，j））））
 enddo 
 enddo 
  

gfortran将接受编译时选项来更改行长限制，但为了可读性和可移植性，最好在默认限制内使用 continuation 。

its showing Expected a right parenthesis in expression, although i have checked it many times

do i= 0, m-1
  do j= 0, n-1
k1(i,j)=-0.001*(((y(i,j)/dx)*((0.02651995*pho(i+3,j))-(0.18941314*pho(i+2,j))+(0.79926643*pho(i+1,j))-(0.79926643*pho(i-1,j))+(0.18941314*pho(i-2,j))-(0.02651995*pho(i-3,j))))+((x(i,j)/dy)*((0.02651995*pho(i+3,j))-(0.18941314*pho(i+2,j))+(0.79926643*pho(i+1,j))-(0.79926643*pho(i-1,j))+(0.18941314*pho(i-2,j))-(0.02651995*pho(i-3, j)))))
  enddo
enddo

解决方案

If your question is "why?", then note that Fortran specifies a maximum line length (if the line consists solely of characters of default kind): 72 for fixed-form source and 132 for free-form source. You don't say which you are using, or how the lines are indented, but the location of the "(1)" in the error message will give a good indication as to whether this is your problem.

gfortran will accept a compile-time option to change the line length limit, but for readability and portability it will be best to break the line within the default limit, using continuation.

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