期望中的正则表达式 [英] Regular expressions in expect

问题描述

我刚刚开始学习期望脚本.我一直在尝试从输出中提取以下内容:

I just started learning expect scripting.I have been trying to extract the following from my output:

core.4046140998.01.10.133211

使用以下命令使用期望脚本.有人可以告诉我我要去哪里了吗?我想将整个字符串ie(core.4046140998.01.10.133211 *)存储在变量中并执行一些操作

with an expect script using the following command.can somebody please tell me where I am going wrong?I want to get to store this entire string i.e.( core.4046140998.01.10.133211*) in a variable and perform some action with it.

expect -re {^(core)\.*} {puts $expect_out(0,string)}

我是否需要导入任何软件包才能使它正常工作?

Do i have to import any packages in expect to make this work?

推荐答案

由于这是预期的，因此"core"可能出现在行的开头，而不是出现在输入字符串的开头 .演示:

Since this is expect, "core" may appear at the beginning of a line, but not at the beginning of the input string. To demonstrate:

$ expect
expect1.1> spawn sh
spawn sh
8043
expect1.2> send "echo core.1234\r"
expect1.3> exp_internal 1
expect1.4> expect -re {^core.*}
Gate keeper glob pattern for '^core.*' is 'core*'. Activating booster.

expect: does "" (spawn_id exp6) match regular expression "^core.*"? Gate "core*"? gate=no
sh-4.3$ echo core.1234
core.1234
sh-4.3$ 
expect: does "sh-4.3$ echo core.1234\r\ncore.1234\r\nsh-4.3$ " (spawn_id exp6) match regular expression "^core.*"? Gate "core*"? gate=yes re=no
expect: timed out
expect1.5> expect -re {(?n)^core.*}
Gate keeper glob pattern for '(?n)^core.*' is 'core*'. Activating booster.

expect: does "sh-4.3$ echo core.1234\r\ncore.1234\r\nsh-4.3$ " (spawn_id exp6) match regular expression "(?n)^core.*"? Gate "core*"? gate=yes re=yes
expect: set expect_out(0,string) "core.1234\r"
expect: set expect_out(spawn_id) "exp6"
expect: set expect_out(buffer) "sh-4.3$ echo core.1234\r\ncore.1234\r"
expect1.6> puts ">>>$expect_out(0,string)<<<"
<<<core.1234

注意事项:

• 期望-re {^core.*}不匹配.我们看到超时"消息

• 请注意我们要匹配的内容:

• expecting -re {^core.*} did not match. We see the "timed out" message

• note what we're attempting to match:

expect: does "sh-4.3$ echo core.1234\r\ncore.1234\r\nsh-4.3$ " (spawn_id exp6) match regular expression "^core.*"? Gate "core*"? gate=yes re=no
# ............^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

它以我发送的命令开头，因此使用普通"锚将不起作用

It starts with the command I sent, so using a "normal" anchor won't work

我接下来要期待的是-re {(?n)^core.*}. 匹配.

the next thing I expect is -re {(?n)^core.*}. This does match.

• (?n)是很少使用的 Tcl正则表达式告诉正则表达式引擎我们需要换行敏感"匹配的指令.
• 对换行符敏感的匹配意味着.将不匹配换行符，并且(在此处更相关)^可以在多行字符串中的换行符之后立即匹配(与$类似)

• the (?n) is a little-used Tcl regex instruction that tells the regex engine we want "newline-sensitive" matching.
• newline-sensitive matching means that . will not match a newline and (more relevant here) that ^ can match immediately after a newline within a multi-line string (similarly for $)

这里的外卖课程是:

• 很难提取命令的输出，因为提示和发送的命令可能会妨碍您.
• 使用期望调试"来查看为什么您的模式不匹配.

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