为什么我的函数将布尔值更改为'on'？ [英] Why is my function changing boolean value to 'on'?
问题描述
我想将下面的代码转换为我可以调用的函数。它的工作原理与下面一样，如果我检查我的表单中的复选框，则输出1，如果我不触摸我的复选框，它将保持为0。
$ activeMain =（isset（$ _ POST ['activateBox']））？ $ _POST ['activateBox']：false;
if（$ activeMain == true）{
$ activeMain ='1';
}
然而，当我尝试使用函数来做同样的事情时，我选择我的复选框显示'1'，它仍然是0，如果我做了一个var_dump输出现在是开，而不是1，如它应该是。
<下面是我试过的功能：
函数activeCheck（$ activeMain）{
$ activeMain =（isset（$ _ POST ['activateBox']））？ $ _POST ['activateBox']：false;
if（$ activeMain == true）{
$ activeMain ='1';
}
return $ activeMain; //我使用返回值
搞砸了，据我所知，它没有任何作用。
} //结束activeCheck函数
activeCheck（$ activeMain）; //调用函数
总而言之，当我尝试使用函数以及如何使其工作时，为什么它会显示on。
编辑：
如何将我的原始代码（上面的代码的第一位） ？
我应该使用哪些值/我可以使用除_SESSION之外的其他值来检查用户是否已从表单中选中复选框？
我有一个HTML / PHP表单，我可以选择一个复选框。如果用户点击复选框，他们提供的输入将输出一个真值1。
我的HTML / PHP表单：
<？php session_start （）; ？>
<！DOCTYPE HTML>
< HTML>
< head>
< title> PHP FORM< / title>
< / head>
< body>
< form method =postaction =processForm.php>
名称：< input type =textname =namesrequired =required>< br>
< input type =submitvalue =创建用户onclick =formNAMES>< br>
激活：< input type =checkboxname =activateBox>
<？php
if（isset（$ _ SESSION ['error']））{
foreach（$ _SESSION ['error'] as $ value）{
echo $ value;
}
session_destroy（）;
unset（$ _ SESSION ['error']）;
}
/ *上面if语句检查是否在processForm页面中设置了$ _SESSION变量。如果有，
对应于错误的错误信息显示在重定向到这个表单上。未设置确保
$ _SESSION在完成该过程后被销毁。 * /
？>
< / form>
< / body>
< / html>
将相关行更改为以下内容：
$ activeMain = isset（$ _ POST ['activateBox']）;
更新：请检查这一个。
function activeCheck（）{
return isset（$ _ POST ['activateBox']）;
}
activeCheck（）;
由于更新问题而更新的答案：
我删除了 session_destory 如果你执行该操作，并且你有另一个会话变量ex： user isLoggedIn ，它也会被销毁。为此， unset 可以。请根据最佳实践检查XSS，围绕互联网实施逻辑的Sql注入攻击，以及在将进程参数存入数据库之前对您的数据进行验证/清理等。
<？php
// formView.php
ob_start（）;
session_start（）;
？>
<！DOCTYPE HTML>
< HTML>
< head>
< title> PHP FORM< / title>
< / head>
< body>
< form method =POSTaction =processForm.php>
名称：< input type =textname =namesrequired =required>< br>
< input type =submitvalue =创建用户onclick =formNAMES>< br>
激活：< input type =checkboxname =activateBox>
<？php
if（isset（$ _ SESSION ['error']））{
foreach（$ _SESSION ['error'] as $ value）{
echo $ value;
}
unset（$ _ SESSION ['error']）;
}
/ *上面if语句检查是否在processForm页面中设置了$ _SESSION变量。如果有，
对应于错误的错误信息显示在重定向到这个表单上。未设置确保
$ _SESSION在完成该过程后被销毁。 * /
？>
< / form>
< / body>
< / html>
<？php ob_end_clean（）; ？>
$ php
// processForm.php
if（！empty（$ _ POST））{
$ safeParameters = [];
foreach（$ _POST as $ key => $ val）{
//清理输入。 @请参阅XSS，SQL注入等。
//根据您的需要验证参数。
$ safeParameters [$ key] = $ val;
}
$ _POST = [];
checkIsActivated（$ safeParameters）;
//实现其他逻辑，
//将表单保存到数据库等
}
函数checkIsActivated（$ parameters）
{
return！empty（$ parameters ['activateBox']）;
}
？>
So I'm new to php/the programming world and I'm studying online and other forms and such but I couldn't find anything to help answer my question which is why I'm here. Any help is certainly appreciated, Thanks!
I want to turn the below code into a function that I can call. It works just as it stands below as in it outputs a 1 if I check my check box in my form and remains 0 if I don't touch my checkbox.
$activeMain = (isset($_POST['activateBox'])) ? $_POST['activateBox'] : false;
if ($activeMain == true) {
$activeMain = '1';
}
However when I try to use a function to do the same thing, and I select my checkbox to display a '1', it remains 0 and if I do a var_dump the output is now "on" instead of 1 like how it is supposed to be.
Below is the function I tried:
function activeCheck($activeMain) {
$activeMain = (isset($_POST['activateBox'])) ? $_POST['activateBox'] : false;
if ($activeMain == true) {
$activeMain = '1';
}
return $activeMain;//I messed around with a return value
and as far as I can tell, it has no effect.
}//ends activeCheck function
activeCheck($activeMain);//call to function
In all I'm confused on why it shows "on" when I try to use a function as well as how to get it to work.
EDIT:
How do I turn my original code (first bit of code posted above) into a function? What values should I use / can I use something else besides _SESSION to check if user has selected the checkbox from the form?
I have a HTML/PHP form in which I give the option to select a checkbox. If users hit the checkbox, the input they provided will output a '1' for a true value.
My HTML/PHP form:
<?php session_start(); ?>
<!DOCTYPE HTML>
<HTML>
<head>
<title>PHP FORM</title>
</head>
<body>
<form method="post" action="processForm.php">
Name: <input type="text" name="names" required = "required"><br>
<input type="submit" value="Create Users" onclick="formNAMES"><br>
Activate: <input type="checkbox" name="activateBox">
<?php
if (isset($_SESSION ['error'])) {
foreach ($_SESSION['error'] as $value) {
echo $value;
}
session_destroy();
unset($_SESSION['error']);
}
/* Above if statement checks if $_SESSION variable has been set in processForm page. If it has,
an error message corresponding to the error shows up on redirect to this form. The unset makes sure
the $_SESSION is destroyed upon completion of the process. */
?>
</form>
</body>
</html>
Change related line to following: The problem is when activateBox is not empty it assings itself to $activeMain naturally.
$activeMain = isset($_POST['activateBox']);
Updated : Check this one.
function activeCheck() {
return isset($_POST['activateBox']);
}
activeCheck();
Updated Answer Due To Updated Question :
I removed session_destory if you execute that and if you have another session variable ex: user isLoggedIn it would be destroyed too. unset is OK for the purpose. Please check XSS, Sql injection attacks around the internet implement logic according to best practises, and validate/sanitize your data before process parameters into DB or etc.
<?php
// formView.php
ob_start();
session_start();
?>
<!DOCTYPE HTML>
<HTML>
<head>
<title>PHP FORM</title>
</head>
<body>
<form method="POST" action="processForm.php">
Name: <input type="text" name="names" required = "required"><br>
<input type="submit" value="Create Users" onclick="formNAMES"><br>
Activate: <input type="checkbox" name="activateBox">
<?php
if (isset($_SESSION ['error'])) {
foreach ($_SESSION['error'] as $value) {
echo $value;
}
unset($_SESSION['error']);
}
/* Above if statement checks if $_SESSION variable has been set in processForm page. If it has,
an error message corresponding to the error shows up on redirect to this form. The unset makes sure
the $_SESSION is destroyed upon completion of the process. */
?>
</form>
</body>
</html>
<?php ob_end_clean(); ?>
<?php
// processForm.php
if (!empty($_POST)) {
$safeParameters = [];
foreach ($_POST as $key => $val) {
// sanitize your inputs. @see XSS, SQL injection etc.
// validate parameters according to your needs.
$safeParameters[$key] = $val;
}
$_POST = [];
checkIsActivated($safeParameters);
// implement other logic,
// save form to database etc.
}
function checkIsActivated($parameters)
{
return !empty($parameters['activateBox']);
}
?>
这篇关于为什么我的函数将布尔值更改为'on'？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
