函数获取python中的动物数量 [英] Function to get the number of animals in python

问题描述

你好这些函数根据这两只动物的头和腿的输入返回猪和鸡的数量。我对Python非常陌生。我无法理解它是如何工作的。你能详细解释一下吗？

  def solve（numLegs，numHeads）：
在numChick范围内（0，numHeads + 1）：
 numPigs = numHeads  -  numChicks 
 totLegs = 4 * numPigs + 2 * numChicks 
如果totLegs == numLegs：
返回[numPigs，numChicks] 
 return [None，None] 
 $ b $ def barnYard（）：
 heads = int（raw_input（'输入头数：'））
 legs = int（raw_input（'输入腿数：'） ）
猪，鸡=解决（腿，头）
如果猪=无：
打印'没有解决方案'
其他：
 print'猪的数量：'，pigs 
 pirnt'chickes数量：'，chickens 
  

所以当我运行谷仓功能它问头数，所以我把20头，然后把56腿。它打印猪的数量8和数量鸡12.但我真的不明白它是如何达到这个阶段。特别是 solve（）函数。帮助将不胜感激。

解决方案

基本上：

  def solve（numLegs，numHeads）：
在numChick范围内（0，numHeads + 1）：＃对于范围0中的每个数字 - 头数+ 1，numChick =该数字
 numPigs = numHeads  -  numChicks＃猪的数量等于输入的头数减去当前数字
 totLegs = 4 * numPigs + 2 * numChicks＃腿的数量是4（腿的数量）*头数+ 2 （鸡腿）*当前数字
如果totLegs == numLegs：如果猪腿+鸡腿=腿的总数，
返回[numPigs，numChicks]＃返回猪的数量和鸡
 return [None，None] #else，返回none，触发no solution
 $ b $ def barnYard（）：
 heads = int（raw_input（'Enter the number of heads ：'））＃
 legs = int（raw_input（'输入腿数：'））
 pigs，chickens = solve（legs，heads）
 if pigs = No ne：
 print'没有解决方案'
 else：
 print'猪的数量：'，猪
 pirnt'鸡的数量：'，鸡
  

所以：

基本上，它会运行该函数并且直到计算出的腿的数量等于输入的腿的总量。如果它永远不等于，它只会返回[none，none]。 （返回[numPigs，numChicks]打破for循环）

编辑：
我试着拿出第2行的+1它仍然工作得很好。

Hello these functions return the number of pigs and chickens based on the input of these two animals' heads and legs. I am really new to python. I can't understand how it works. Can you explain this elaborately?

def solve(numLegs, numHeads):
    for numChick in range(0, numHeads + 1):
        numPigs = numHeads - numChicks
        totLegs = 4 * numPigs + 2* numChicks
        if totLegs == numLegs:
           return [numPigs, numChicks]
    return[None, None]

def barnYard():
    heads = int(raw_input('Enter number of heads:'))
    legs = int(raw_input('Enter number of legs:'))
    pigs, chickens = solve(legs, heads)
    if pigs = None:
       print 'there is no solution'
    else:
        print 'number of pigs:' , pigs
        pirnt 'number of chickes:', chickens

So when i run the barnYard function it asks number of heads so i put 20 heads and then put 56 legs. It prints number of pigs 8 and number chickens 12. But i really can't understand how it reaches at this stage. Specially the solve() function. Help will be appreciated.

解决方案

Basically:

def solve(numLegs, numHeads):
    for numChick in range(0, numHeads + 1): #for every number in the range 0 - the number of heads + 1, numChick = that number
        numPigs = numHeads - numChicks #the number of Pigs equals the number of heads entered minus the current number
        totLegs = 4 * numPigs + 2* numChicks #the amount of legs is 4(amount of legs) * number of heads + 2(chicken legs) * the current number
        if totLegs == numLegs: if the pigs legs + the chicken legs = the total number of legs, 
           return [numPigs, numChicks] #return the number of pigs and chickens
    return[None, None] #else, return none, triggering "no solution"

def barnYard():
    heads = int(raw_input('Enter number of heads:')) #
    legs = int(raw_input('Enter number of legs:'))
    pigs, chickens = solve(legs, heads)
    if pigs = None:
       print 'there is no solution'
    else:
        print 'number of pigs:' , pigs
        pirnt 'number of chickes:', chickens

So:

Basically, it will run the function over and over until the amount of legs calculated equals the total amount of legs entered. If it never equals up, it just returns [none, none]. (return [numPigs, numChicks] breaks the for loop)

Edit: I tried taking out the +1 in line 2 and it still worked just fine.

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