我如何将一个函数应用到数组并形成两个单独的数组？ [英] How do I apply a function to an array and form two separate arrays?

问题描述

我使用Ruby 2.4。我有一个字符串数据元素的数组，看起来像

I'm using Ruby 2.4. I have an array with string data elements, that look like

["a word1 word2", "b eff", "a idaho orange", "new old shoe", "b mars", ...]

我想从上面形成两个数组，将一个函数（ .split（/ ^（a | b）[[：space]] * / i ）应用于然而，我不知道如何形成两个单独的数组。下面的

I want to form two arrays from the above, applying a function (.split(/^(a|b)[[:space]]*/i) to each element of the array. However, I can't figure out how to form two separate arrays. The following

arr.map{ |x| x.split(/^(a|b)[[:space]]*/i) }

只会产生一个数组，并且在每个元素的前面都有一个空元素。理想情况下，我希望输出是两个数组，如

only results in a single array and has a blank element in front of each element. Ideally, I'd like the output to be two arrays like

["a", "b", "a", "", "b", ...]
["word1 word2", "eff", "idaho orange", "new old shoe", "mars", ...]

推荐答案

试试这个

arr.map { |x| a, b, c = x.partition(/^[ab]\s+/); [b.strip, a + c] }.transpose

这是如何工作的？

• 分区将字符串拆分为before-match，match和后续匹配


• b.strip 是没有尾随空白的匹配


• a + c 是完整字符串（如果没有匹配，则完整字符串在匹配前）或后期匹配


• [...，...] 创建一个元组，因此创建一个元组数组


• 转置切换2D数组的行和列

• partition splits a string into before-match, match and post-match
• b.strip is the match without trailing whitespace
• a + c is either the full string (if there was no match the full string is in before-match) or the post-match
• [..., ...] creates a tuple, hence creating an array of tuple
• transpose switches the rows and columns of a 2D array

这篇关于我如何将一个函数应用到数组并形成两个单独的数组？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！